-1
<!DOCTYPE html>
<html>
<body>
<div align="center" style="width:800px" >
LocalShare:
<input type="file" id="FileUpload" onchange="selectFolder(event)" webkitdirectory mozdirectory multiple />
<p id="demo"></p>
<p id="demo1"></p>
<script>
function selectFolder(e) {
var txt = "";
var theFiles = e.target.files;
var relativePath = theFiles[0].webkitdirectory;
var relativePath = theFiles[0].webkitRelativePath;
var x = document.getElementById("FileUpload").value;
document.getElementById("demo").innerHTML = x;
document.getElementById("demo1").innerHTML = relativePath;
var folder = relativePath.split("/");
alert(folder[0]);
}
</script>
</body>
</html>
上面的代码的输出是:如何获取使用javascript上传的文件夹的完整路径名?
C:\ fakepath \文件名
FOLDERNAME
在这里它显示文件夹名和路径名。它将默认值设置为“假路径”,但我需要找出确切的路径!
纠正我,如果我错了,但我不确定这是否可能使用JavaScript的安全目的。 – Script47