如何从复杂json访问元素

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hello 从2-3天开始，iam陷入了一个新问题，实际上我必须使用'api url'来检索复杂的json数组，它就像这样 -如何从复杂json访问元素

{"response":{"success":true,"result":{"id":"45203511","device_id":"62970","message":"Rs. 20.00 refunded in your Paytm wallet for your order on Paytm. Updated balance:Rs. 20.0. Queries? Visit Paytm.com\/care.","status":"received","send_at":0,"queued_at":0,"sent_at":0,"delivered_at":0,"expires_at":0,"canceled_at":0,"failed_at":0,"received_at":1507375388,"error":"N\/A","created_at":1507375388,"contact":{"id":"9209301","name":"VK-IPAYTM","number":"VK-IPAYTM"}}},"status":200}

我想从此json打印一个元素到控制台 “console.log（data）;” 此代码在控制台中打印整个数组，但我必须仅打印“id”元素。请帮助我！

来源

2017-10-08 Kalpit rathore

“我只打印‘身份证’元素”

你的数据是嵌套对象，因此要获得任何对象的属性，你可以做object.property或object["property"]。这里是一个例子，如何让id属性：

var obj = {"response":{"success":true,"result":{"id":"45203511","device_id":"62970","message":"Rs. 20.00 refunded in your Paytm wallet for your order on Paytm. Updated balance:Rs. 20.0. Queries? Visit Paytm.com/care.","status":"received","send_at":0,"queued_at":0,"sent_at":0,"delivered_at":0,"expires_at":0,"canceled_at":0,"failed_at":0,"received_at":1507375388,"error":"N/A","created_at":1507375388,"contact":{"id":"9209301","name":"VK-IPAYTM","number":"VK-IPAYTM"}}},"status":200} 
 
console.log(obj.response.result.id)

来源

2017-10-08 04:29:27

**它显示的错误： - ** _train2.php：23遗漏的类型错误：无法读取属性 '结果' undefined at Object.fireWith [as resolveWith]（jquery.min.js：2） at A（jquery.min）Object.success（train2.php：23） at i（jquery.min.js：2） .js：4） at XMLHttpRequest。（jquery.min.js：4）_ **我的整个脚本部分是： - ** '' **请帮帮我！** –

@Kalpitrathore，你忘了使用JSON.parse（yourJSONHere）解析你的JSON吗？ https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/JSON/parse –

如何从复杂json访问元素

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