猜猜数字游戏给出的答案太快

Question

我正在学习Python的介绍，并遇到了一个问题。

请看看我的脚本：

import random 
secretNumber = random.randint(1,20) 
print (' I am thinking of a number between 1 and 20.') 

#ask the player to guess 6 times. 
for guessesTaken in range (1,7): 
    print ('take a guess.') 
    guess = int(input()) 

    if guess < secretNumber: 
     print ('your guess is too low') 
    elif guess > secretNumber: 
     print ('your guess is too high') 
    else: 
     break 

    if guess == secretNumber: 
     print ('good job! you guessed my number in ' + str(guessesTaken) + ' guesses!') 
    else: 
     print ('nope. the number i was thinking of was ' + str(secretNumber)) 

我试图做的猜测非数字游戏。当我运行该脚本，它问我：

1. 猜数字

2. 当我在数字输入，它会自动给我它存储的，而不是给我6次尝试我的号码。

如果我在任何步骤都不清楚，请告诉我，下次我会尽全力回答更清晰的问题！

Answer 1

以if guess == secretNumber:开头的最后一部分是循环的一部分，但您不希望在循环中给出最终结果。相反，把它在循环后（外的话），这意味着你应该减少这4行代码的缩进：

import random 
secretNumber = random.randint(1,20) 
print (' I am thinking of a number between 1 and 20.') 

#ask the player to guess 6 times. 
for guessesTaken in range (1,7): 
    print ('take a guess.') 
    guess = int(input()) 

    if guess < secretNumber: 
     print ('your guess is too low') 
    elif guess > secretNumber: 
     print ('your guess is too high') 
    else: 
     break 

if guess == secretNumber: 
    print ('good job! you guessed my number in ' + str(guessesTaken) + ' guesses!') 
else: 
    print ('nope. the number i was thinking of was ' + str(secretNumber)) 

Answer 2

最简单的解决方法是，上面已经为说明，只需将最后的if语句跳出循环。你使用的语法（除了那个错误的缩进）非常好，这是python的一个很好的开始。然而，在python 3中，你不需要在循环内部的if语句中使用其他语言。从根本上说，因为如果满足ELSE条件，你不需要做任何事情，你可以把它拿出来。