2016-05-15 73 views
0

我得到了类似的错误。
未捕获PDOException:SQLSTATE [21000]:基数违规:1241操作数应包含1列(S)未捕获的PDOException:SQLSTATE [21000]:基数违规:1241操作数应该包含1列

if ($_POST['submit'] ?? '' == "Log In") { 

    $query = "SELECT * FROM member WHERE (email, password) LIKE (:email, :password)"; 

    $stmt = $link -> prepare($query); 
    $stmt -> bindValue(':email', $_POST['loginemail'], PDO::PARAM_STR); 
    $stmt -> bindValue(':password', md5(md5($_POST['loginemail']).$_POST['loginpassword']), PDO::PARAM_STR); 
    $stmt -> execute(); 
    $rows = $stmt -> fetchAll(); 

} 

但没有错误的这一说法。

$sql = "SELECT ko_name FROM dogBREEDS WHERE dogBREEDS.ko_name LIKE (:keyword) ORDER BY id ASC LIMIT 0, 10"; 
$query = $pdo->prepare($sql); 
$query->bindParam(':keyword', $keyword, PDO::PARAM_STR); 
$query->execute(); 
$list = $query->fetchAll(); 

我该如何解决这个问题?和有什么区别?

回答

0

$query = "SELECT * FROM member WHERE (email, password) LIKE (:email, :password)";

这个SQL是不是在正确的语法权SQL。 LIKE(或者看看这里MySQL LIKE Clause)不能使用这样的,试试这个请;)

$query = "SELECT * FROM member WHERE email LIKE (:email) and password LIKE (:password)"; 
0

我只是改变了这个样子。

$query = "SELECT ID FROM member WHERE email=:email AND password=:password"; 

$stmt = $link -> prepare($query); 
$stmt -> bindParam(':email', $_POST['loginemail'], PDO::PARAM_STR); 
$stmt -> bindValue(':password', md5(md5($_POST['loginemail']).$_POST['loginpassword']), PDO::PARAM_STR); 
$stmt -> execute(); 
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