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我在java脚本中有一个数组，该数组有文件名和文件路径，现在我必须在php中分配该数组并上传该数组存储在哪个文件中，我可以吗请给我解决方案。如何在php中使用javascript数组上传多个图像
这是我的javascript
<script type="text/javascript">
var arrImgNPath = [];
var arrUniqueIds = [];
function myFunction() {
var files = $('#filesID').prop("files");
var names = $.map(files, function(val) { return val.name; });
console.log(names);
console.log("N the final result is :");
for (var i=0; i<arrImgNPath.length; i++){
var dict = arrImgNPath[i];
//$('#str').val(JSON.stringify(dict));
console.log("obj value :",dict);
}
}
function removeImageDataFromArray(spanId){
console.log("spanID--------------------------------------"+spanId);
arrImgNPath= arrImgNPath.filter(function(el) { return el.ID != spanId; });
for (var i=0; i<arrImgNPath.length; i++){
var dict = arrImgNPath[i];
console.log("obj value :",dict);
}
}
function uniqId() {
while (1) {
var uid = Math.round(new Date().getTime() + (Math.random() * 100));
var isPresent = false;
for(var i=0; i<arrUniqueIds.length; i++){
var idFromArray = arrUniqueIds[i];
if (uid == idFromArray){
isPresent = true;
}
}
if (isPresent === false) {
return uid;
}
}
}
$(document).ready(function() {
if (window.File && window.FileList && window.FileReader) {
$("#filesID").on("change", function(e) {
var files = e.target.files,
filesLength = files.length;
//console.log(files);
var filePath = $(this).val();
//console.log("fake pathddddddddddd"+filePath);
for (var i = 0; i < filesLength; i++) {
var tmppath = URL.createObjectURL(event.target.files[0]);
filePath =tmppath;
var f = files[i];
var randomId = uniqId();
var dict = {};
dict.name = f.name;
dict.path = filePath;
dict.ID = randomId;
arrImgNPath[arrImgNPath.length] = dict;
var fileReader = new FileReader();
fileReader.onload = (function(e) {
var file = e.target;
//console.log("bfsd dsf sdfdsfds"+e.target.result);
// console.log("adsfdsfsd fsdf sdfsdfsdfsdsdfd"+randomId);
$("<span id=\"" + randomId + "\" class=\"pip\" >" +
"<img class=\"imageThumb\" src=\"" + e.target.result + "\" title=\"" + file.name + "\"/>" +
"<br/><span class=\"remove\">Remove image</span>" +
"</span>").insertAfter("#filesID");
$(".remove").click(function(){
//$(this).find("span").attr("id", "myspan_"+i);
console.log("files id values :"+ $(this).parent(".pip").attr("id"));
removeImageDataFromArray($(this).parent(".pip").attr("id"));
$(this).parent(".pip").remove();
});
});
fileReader.readAsDataURL(f);
}
});
} else {
alert("Your browser doesn't support to File API");
}
});
</script>
字典是我的数组如何分配在PHP数组和上传文件， 你可以在控制台检查骑上值
php文件
<!DOCTYPE html>
<head>
<style>
input[type="file"] {
display: block;
}
.imageThumb {
max-height: 75px;
border: 2px solid;
padding: 1px;
cursor: pointer;
}
.pip {
display: inline-block;
margin: 10px 10px 0 0;
}
.remove {
display: block;
background: #444;
border: 1px solid black;
color: white;
text-align: center;
cursor: pointer;
}
.remove:hover {
background: white;
color: black;
}
</style>
</head>
<body>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="field" align="left">
<form method="post" enctype="multipart/form-data" >
<h3>Upload your images</h3>
<input type="file" id="filesID" name="files[]" size="150" multiple="multiple" >
<input type="submit" name="submit" >
<input type="button" onclick="myFunction()" value="clickMe">
</form>
</div>
无论何时单击clickMe按钮，您可以在控制台中检查文件名和文件路径，请帮助我
哪里可以发送邮件发送到？ – elpddev
@elpddev先生没有形式，这是主要原因，我该怎么做呢？ –
可以通过为JS函数创建的每个span元素创建''来完成。然后通过'$ _POST ['yourName']'从另一个php文件获取值。但要做到这一点，我们必须知道你想先发送哪些值。目前有两个值ID和图像路径。你想把它们都寄给他们吗？ –