2008-09-16 80 views

回答

233

从小数到十六进制转换做...

string hexValue = decValue.ToString("X"); 

从十六进制转换为十进制做要么...

int decValue = int.Parse(hexValue, System.Globalization.NumberStyles.HexNumber); 

int decValue = Convert.ToInt32(hexValue, 16); 
+1

我想了解这条线decV​​alue.ToString(“X”)如何将它转换为十六进制。 – gizgok 2010-12-07 08:45:45

+20

变量decValue的类型是Int32。 Int32有一个ToString()重载,它可以接受大量格式字符串中的一个,这些格式字符串指示值将如何表示为字符串。 “X”格式字符串表示十六进制,因此255.ToString(“X”)将返回十六进制字符串“FF”。欲了解更多信息,请参阅http://msdn.microsoft.com/en-us/library/dwhawy9k.aspx – 2010-12-07 09:07:47

+2

Convert.ToInt32比int.Parse(...) – 2012-02-03 09:58:16

1
String stringrep = myintvar.ToString("X"); 

int num = int.Parse("FF", System.Globalization.NumberStyles.HexNumber); 
22

看起来你可以说

Convert.ToInt64(value, 16) 

摆脱hexdecimal小数。

其他的方式是:

otherVar.ToString("X"); 
+0

我得到System.FormatException:指定的格式'x'无效 – 2018-02-12 11:25:41

2

From Geekpedia

// Store integer 182 
int decValue = 182; 

// Convert integer 182 as a hex in a string variable 
string hexValue = decValue.ToString("X"); 

// Convert the hex string back to the number 
int decAgain = int.Parse(hexValue, System.Globalization.NumberStyles.HexNumber); 
47

十六进制 - >十进制:

Convert.ToInt64(hexValue, 16); 

十进制 - >六角

string.format("{0:x}", decValue); 
+4

+1 Convert.ToInt64(hexValue,16)的好处;``如果'0x'前缀是否存在,而其他一些解决方案则不会。 – Craig 2012-01-04 12:53:45

+0

@Craig嗨,所以我需要根据十六进制值大小进行转换,或者我可以将ToInt64应用于所有十六进制值,会有什么影响吗? – user1219310 2014-08-27 14:07:50

3
static string chex(byte e)     // Convert a byte to a string representing that byte in hexadecimal 
    { 
     string r = ""; 
     string chars = "ABCDEF"; 
     r += chars[e >> 4]; 
     return r += chars[e &= 0x0F]; 
    }   // Easy enough... 

    static byte CRAZY_BYTE(string t, int i)  // Take a byte, if zero return zero, else throw exception (i=0 means false, i>0 means true) 
    { 
     if (i == 0) return 0; 
     throw new Exception(t); 
    } 

    static byte hbyte(string e)     // Take 2 characters: these are hex chars, convert it to a byte 
    {           // WARNING: This code will make small children cry. Rated R. 
     e = e.ToUpper(); // 
     string msg = "INVALID CHARS";   // The message that will be thrown if the hex str is invalid 

     byte[] t = new byte[]     // Gets the 2 characters and puts them in seperate entries in a byte array. 
     {          // This will throw an exception if (e.Length != 2). 
      (byte)e[CRAZY_BYTE("INVALID LENGTH", e.Length^0x02)], 
      (byte)e[0x01] 
     }; 

     for (byte i = 0x00; i < 0x02; i++)  // Convert those [ascii] characters to [hexadecimal] characters. Error out if either character is invalid. 
     { 
      t[i] -= (byte)((t[i] >= 0x30) ? 0x30 : CRAZY_BYTE(msg, 0x01));         // Check for 0-9 
      t[i] -= (byte)((!(t[i] < 0x0A)) ? (t[i] >= 0x11 ? 0x07 : CRAZY_BYTE(msg, 0x01)) : 0x00);  // Check for A-F 
     }   

     return t[0x01] |= t[0x00] <<= 0x04;  // The moment of truth. 
    } 
2

这是不是最简单的方法,但是这个源代码使你能够正确的任何类型的八进制数,即23.214, 23和0.512等等。希望这将帮助你..

public string octal_to_decimal(string m_value) 
    { 
     double i, j, x = 0; 
     Int64 main_value; 
     int k = 0; 
     bool pw = true, ch; 
     int position_pt = m_value.IndexOf("."); 
     if (position_pt == -1) 
     { 
      main_value = Convert.ToInt64(m_value); 
      ch = false; 
     } 
     else 
     { 
      main_value = Convert.ToInt64(m_value.Remove(position_pt, m_value.Length - position_pt)); 
      ch = true; 
     } 

     while (k <= 1) 
     { 
      do 
      { 
       i = main_value % 10;          // Return Remainder 
       i = i * Convert.ToDouble(Math.Pow(8, x));     // calculate power 
       if (pw) 
        x++; 
       else 
        x--; 
       o_to_d = o_to_d + i;          // Saving Required calculated value in main variable 
       main_value = main_value/10;        // Dividing the main value 
      } 
      while (main_value >= 1); 
      if (ch) 
      { 
       k++; 
       main_value = Convert.ToInt64(Reversestring(m_value.Remove(0, position_pt + 1))); 
      } 
      else 
       k = 2; 
      pw = false; 
      x = -1; 
     } 
     return (Convert.ToString(o_to_d)); 
    }  
0

如果这是一个非常大的十六进制字符串超出了正常的整数的能力:

对于.NET 3.5中,我们可以使用BouncyCastle的的的BigInteger类:

String hex = "68c7b05d0000000002f8"; 
// results in "494809724602834812404472" 
String decimal = new Org.BouncyCastle.Math.BigInteger(hex, 16).ToString(); 

.NET 4.0有BigInteger类。

-1

将字节数组转换为十六进制表示的扩展方法。这填充每个字节与前导零。

/// <summary> 
    /// Turns the byte array into its Hex representation. 
    /// </summary> 
    public static string ToHex(this byte[] y) 
    { 
     StringBuilder sb = new StringBuilder(); 
     foreach (byte b in y) 
     { 
      sb.Append(b.ToString("X").PadLeft(2, "0"[0])); 
     } 
     return sb.ToString(); 
    } 
11

如果你想要最大的性能从十六进制转换做时,十进制数,你可以用十六进制到十进制值的预填充表的方法。

下面是说明这个想法的代码。我performance tests表明,它可以比Convert.ToInt32快-40%20%(......):

class TableConvert 
    { 
     static sbyte[] unhex_table = 
     { -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 
     ,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 
     ,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 
     , 0, 1, 2, 3, 4, 5, 6, 7, 8, 9,-1,-1,-1,-1,-1,-1 
     ,-1,10,11,12,13,14,15,-1,-1,-1,-1,-1,-1,-1,-1,-1 
     ,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 
     ,-1,10,11,12,13,14,15,-1,-1,-1,-1,-1,-1,-1,-1,-1 
     ,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 
     }; 

     public static int Convert(string hexNumber) 
     { 
      int decValue = unhex_table[(byte)hexNumber[0]]; 
      for (int i = 1; i < hexNumber.Length; i++) 
      { 
       decValue *= 16; 
       decValue += unhex_table[(byte)hexNumber[i]]; 
      } 
      return decValue; 
     } 
    } 
0

这里是我的功能:

using System; 
using System.Collections.Generic; 
class HexadecimalToDecimal 
{ 
    static Dictionary<char, int> hexdecval = new Dictionary<char, int>{ 
     {'0', 0}, 
     {'1', 1}, 
     {'2', 2}, 
     {'3', 3}, 
     {'4', 4}, 
     {'5', 5}, 
     {'6', 6}, 
     {'7', 7}, 
     {'8', 8}, 
     {'9', 9}, 
     {'a', 10}, 
     {'b', 11}, 
     {'c', 12}, 
     {'d', 13}, 
     {'e', 14}, 
     {'f', 15}, 
    }; 

    static decimal HexToDec(string hex) 
    { 
     decimal result = 0; 
     hex = hex.ToLower(); 

     for (int i = 0; i < hex.Length; i++) 
     { 
      char valAt = hex[hex.Length - 1 - i]; 
      result += hexdecval[valAt] * (int)Math.Pow(16, i); 
     } 

     return result; 
    } 

    static void Main() 
    { 

     Console.WriteLine("Enter Hexadecimal value"); 
     string hex = Console.ReadLine().Trim(); 

     //string hex = "29A"; 
     Console.WriteLine("Hex {0} is dec {1}", hex, HexToDec(hex)); 

     Console.ReadKey(); 
    } 
} 
0

我的版本是我想多一点因为我的C#知识不是很高。 我使用这个算法:http://easyguyevo.hubpages.com/hub/Convert-Hex-to-Decimal(实施例2)

using System; 
using System.Collections.Generic; 

static class Tool 
{ 
    public static string DecToHex(int x) 
    { 
     string result = ""; 

     while (x != 0) 
     { 
      if ((x % 16) < 10) 
       result = x % 16 + result; 
      else 
      { 
       string temp = ""; 

       switch (x % 16) 
       { 
        case 10: temp = "A"; break; 
        case 11: temp = "B"; break; 
        case 12: temp = "C"; break; 
        case 13: temp = "D"; break; 
        case 14: temp = "E"; break; 
        case 15: temp = "F"; break; 
       } 

       result = temp + result; 
      } 

      x /= 16; 
     } 

     return result; 
    } 

    public static int HexToDec(string x) 
    { 
     int result = 0; 
     int count = x.Length - 1; 
     for (int i = 0; i < x.Length; i++) 
     { 
      int temp = 0; 
      switch (x[i]) 
      { 
       case 'A': temp = 10; break; 
       case 'B': temp = 11; break; 
       case 'C': temp = 12; break; 
       case 'D': temp = 13; break; 
       case 'E': temp = 14; break; 
       case 'F': temp = 15; break; 
       default: temp = -48 + (int)x[i]; break; // -48 because of ASCII 
      } 

      result += temp * (int)(Math.Pow(16, count)); 
      count--; 
     } 

     return result; 
    } 
} 

class Program 
{ 
    static void Main(string[] args) 
    { 
     Console.Write("Enter Decimal value: "); 
     int decNum = int.Parse(Console.ReadLine()); 

     Console.WriteLine("Dec {0} is hex {1}", decNum, Tool.DecToHex(decNum)); 

     Console.Write("\nEnter Hexadecimal value: "); 
     string hexNum = Console.ReadLine().ToUpper(); 

     Console.WriteLine("Hex {0} is dec {1}", hexNum, Tool.HexToDec(hexNum)); 

     Console.ReadKey(); 
    } 
} 
0

二进制转换为十六进制

Convert.ToString(Convert.ToUInt32(binary1, 2), 16).ToUpper() 
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