我想在for
循环中运行MySQL更新查询后显示验证消息。我在下面写了源代码,但验证消息没有显示出来。我不知道什么是问题。PHP代码正常工作,但验证消息未显示
这是我的PHP代码显示的任何输出前
<?php
// Update All rows start
for ($i=0; $i<$setTotalRows ; $i++)
{
$GetChecked = isset($_POST['txtChecked'.$i]);
$GetTransCode = $_POST['txttransCode'.$i];
$GetTransType = $_POST['txttransSetType'.$i];
$GetTransMethod = $_POST['txtPaymentMethod'.$i];
$SetEncodedDate = date("Y-m-d H:i:s");
if (empty($GetChecked)) { //Start Else
continue;
} else if (!empty($GetChecked) && $GetTransType == "ErrorType") {
continue;
} else {
if($GetTransType == "Debit") { //Check For Cashin Cashout Start
$SetTableName = "tblbank_cashin";
} else {
$SetTableName = "tblbank_cashout";
} //Check For Cashin Cashout End
//Method Start
switch ($GetTransMethod) {
case "1":
$SetPayMode = "Cash Deposit";
break;
case "2":
$SetPayMode = "Online Transfer";
break;
case "3":
$SetPayMode = "Cheque Transfer";
break;
case "4":
$SetPayMode = "Cash Withdrawal";
break;
case "5":
$SetPayMode = "Cheque Withdrawal";
break;
default:
$SetPayMode = "Cash Deposit";
}
// Method End
$sql_update = "UPDATE ". $SetTableName. " SET ";
$sql_update .= "transRecon='1'";
$sql_update .= ", transReconDate='$SetEncodedDate'";
$sql_update .= ", transType='$SetPayMode'";
$sql_update .= " WHERE transCode='$GetTransCode'";
$result_reconcile = mysqli_query($conn,$sql_update);
if(!$result_reconcile){
die("SQL Error: " . mysqli_error($conn));
//echo $result_reconcile;
}
} //End Else
} //End For i loop
if(isset($result_reconcile)){
$sucess = "<div class='alert alert-success'><strong><i class='fa fa-check' aria-hidden='true'></i> Perfect!</strong> payment(s) has been reconciled</div>";
header('Refresh: 3;url=banks?P=All&E='.$view_bankid);
} else {
$error_display = "<div class='alert alert-warning'><strong>ERROR!</strong> An error occured. Please Try Again Here</div>";
}
//Update All rows End
?>
那不是你如何做一个重定向以'头()' –
并请学会用[准备好的语句(https://www.youtube.com/watch?v=nLinqtCfhKY)。 –
验证消息在哪里? –