我想将每个数据库放到listview的每一行...... 实际上,我的问题是我能够从数据库中获取数据,但它不能在列表视图中显示出来 my代码:将数据库的每一行映射到listview的每一行
try
{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://10.0.2.2/meetingschedular/fetchmeet.php?uid="+vwname.getText().toString());
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}
catch(Exception e)
{
Toast.makeText(getBaseContext(),e.toString() ,Toast.LENGTH_LONG).show();
}
//Convert response to string
try
{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"UTF-8"));
sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null)
{
sb.append(line + "\n");
}
is.close();
result = sb.toString();
}
catch(Exception e)
{
Toast.makeText(getBaseContext(),e.toString() ,Toast.LENGTH_LONG).show();
}
//END Convert response to string
try
{
JSONArray jArray = new JSONArray(result);
for(int i=0;i<jArray.length();i++)
{
JSONArray innerJsonArray = jArray.getJSONArray(i);
JSONObject json_data = innerJsonArray.getJSONObject(0);
String at1=json_data.getString("title");
String at= json_data.getString("mdate");
String at2=json_data.getString("mtime");
String at3=json_data.getString("venue");
String at4=json_data.getString("organiser");
s.append("\nTitle:"+at1);
s.append("\ndate:"+at);
s.append("\nTime:"+at2);
s.append("\nVenue:"+at3);
s.append("\nOrganiser:"+at4);
r.add(s.toString());
}
l.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, r));}
其显示这样
我想seperately显示每一行。所有行都显示在一行中。 PLS HLP我..
我已经做到了,但没有用,数据库的所有行都显示在单个listview行中。 – priya89 2013-04-30 07:25:54
编辑将'sb'改为's'。尝试为变量使用良好的命名。每当循环运行时,您的当前代码都会附加's',因此您需要重新初始化变量's'。如果你已经改变了你的代码中的任何东西,请更新 – Naveen 2013-04-30 07:36:48
这个问题,非常感谢你的工作....... – priya89 2013-04-30 07:43:05