2017-02-21 51 views
0

请帮我解决这个存储过程做了错误:存储过程MySQL的句法

CREATE DEFINER=`root`@`localhost` PROCEDURE `repos`(IN `order_condition` VARCHAR(100) CHARSET utf8, IN `from_date` VARCHAR(255) CHARSET utf8, IN `to_date` VARCHAR(255) CHARSET utf8, IN `dept_id` TINYINT(4), IN `type` VARCHAR(15) CHARSET utf8, IN `search_value` VARCHAR(50) CHARSET utf8, IN `institutionid` INT(11)) 
    NO SQL 
BEGIN 

set @strWhere = ""; 
set @strWhere = CONCAT(@strWhere,"t1.inst_id = ",instid); 
set @selectstr = ''; 
set @selectstr2 = ''; 
set @joinstr = ''; 
set @joinstr2 = ''; 
set @group2= ''; 

set @selectstr = CONCAT(",t2.`std_name`"); 
set @selectstr2= CONCAT(",t5.`student_name`,t5.`roll_no`,t5.`student_id`"); 
set @joinstr = CONCAT("left join standard_master as t2 on t1.`std_id`= t2.`std_id` "); 
set @joinstr2 = CONCAT("left join student_det as t5 on t1.`std_id`= t5.`std_id` "); 
set @strWhere = CONCAT(@strWhere," AND t1.std_id = ",dept_id); 
set @group2= CONCAT("t5.`student_id`"); 


SET @query = CONCAT("select t1.* ",@selectstr," , t3.term_name, SUM(t4.amount) as fee_amount",@selectstr2," FROM inst_fee AS t1 ",@joinstr," left join term_master as t3 on t1.term_id = t3.term_id left join inst_amtdet as t4 on t4.masterid = t1.masterid ",@joinstr2," WHERE ",@strWhere, " AND ",@group2, " NOT IN (select id from student_master) Group by t1.f_name ", order_condition); 

PREPARE stmt FROM @query; 
EXECUTE stmt; 
DEALLOCATE PREPARE stmt; 

#select @query; 


END 

它显示了一个语法错误:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'IN(

请帮我修正这个错误。谢谢

+0

您的代码没有任何'IN('... –

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参数中有IN。 – Devart

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@Devart是的,但它没有右括号当MySQL报告语法错误时,它总是包含一个字面引号所以这不是真正的消息或它是由不同的代码触发的 –

回答

0

语法无误。它适用于新的MySQL服务器。

您可能会使用旧的MySQL服务器,其中CHARSET子句不支持字符串参数。检查服务器版本的语法。

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Thanks.Ya我已经使用了分隔符,当我尝试保存我得到错误。以保存 – User11

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我已经改变了答案检查它是什么服务器版本 – Devart

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Ya checcked它的5.6.21 – User11