我在摆弄使用Node.js从电子商务网站刮取数据。我使用Request
来检索页面的DOM,并使用Cheerio
来执行服务器端DOM选择。如何在Javascript中添加服务器端延迟for循环?
const cheerio = require('cheerio');
const request = require('request');
// takes a URL, scrapes the page, and returns an object with the data
let scrapePage = (url) => {
return new Promise((resolve, reject) => {
request(url, (error, resp, body) => {
if(error){
reject(error);
};
let $ = cheerio.load(body);
let $url = url;
let $price = $('#rt-mainbody > div > div.details > div.Data > div:nth-child(4) > div.description').text();
let obj = {
url: $url,
price: $price
}
resolve(obj);
});
});
};
// Runs scrapePage in a loop
// There is a variable called arrayOfURLs defined elsewhere that contains 100s of URLs
for(let i = 0; i < arrayOfURLs.length; i++){
scrapePage(arrayOfURLs[i])
.then((obj) => {
//write to a file
})
.catch((error) => {
})
};
的问题是,我将请求发送到服务器有时会发回空白数据,我假设,因为我发送太多的请求,没有任何形式的停顿。由于JS的异步特性,我很难弄清楚如何在循环的每次迭代之间添加有效的延迟。仅仅以同步的方式添加setTimeOut
是不够的,因为setTimeOut
本身是异步的,并且我在服务器上运行它,所以没有Window
对象。
编辑
上面的代码是什么我工作的简化版本。整个代码是这样的:
app.js
const fs = require('fs');
const path = 'urls.txt';
const path2 = 'results.txt';
const scraper = require('./scraper');
let scrapePage = (url) => {
scraper.scrapePage(url)
.then((obj) => {
// console.log('obj from the scraper with Promises was received');
// console.log(obj);
// console.log('writing obj to a file');
fs.appendFile(path2, JSON.stringify(obj) + ', ', (error) => {
if(error){
console.log(error);
} else {
// console.log('Successfully wrote to ' + path2);
}
})
})
.catch((error) => {
console.log('There was an error scraping obj: ');
console.log(error);
})
}
fs.readFile(path, 'utf8', (err, data) => {
if (err){
throw err;
};
var urlArray = JSON.parse(data);
// this returns an Unexpected Identifier error
// const results = await Promise.all(urlArray.map(scrapePage));
// this returns an Unexpected Token Function error
// async function scrapePages(){
// const results = await Promise.all(urlArray.map(scrapePage));
// };
});
scraper.js
const request = require('request');
const cheerio = require('cheerio');
exports.scrapePage = (url) => {
return new Promise((resolve, reject) => {
request(url, (error, resp, body) => {
if(error){
reject(error);
};
let $ = cheerio.load(body);
let $url = url;
let $price = $('#rt-mainbody > div > div.details > div.itemData > div:nth-child(4) > div.description').text();
let obj = {
url: $url,
price: $price
}
resolve(obj);
})
})
}
可能重复[什么是睡眠()的JavaScript版本?](https://stackoverflow.com/questions/951021/what-is-the-javascript-version-of-sleep) –
你不能依靠假设数据将在一定时间后出现在那里。改为使用回调函数尝试一种方法。 – Ctznkane525
我会调查这个空白数据问题,至少记录标题和响应代码,以便找出错误的位置。好像你在猜测,为什么在你知道错误是什么之前进行修改? –