我有一个查询计算是基于此文档的点的一定半径内的对象:http://www.plumislandmedia.net/mysql/haversine-mysql-nearest-loc/perl的错误传递时DBI->执行值IN子句
它的工作原理很漂亮,但是我想只搜索那些特定类型的对象,这会导致问题;
的代码看起来是这样的:
my $sql = "SELECT *
FROM (
SELECT b.*, pr.postcode, pr.prize, pr.title, pr.collection, pr.redeemed, pr.delivery, pr.archived, bt.category,
p.radius,
p.distance_unit
* DEGREES(ACOS(COS(RADIANS(p.latpoint))
* COS(RADIANS(b.lat))
* COS(RADIANS(p.longpoint - b.lng))
+ SIN(RADIANS(p.latpoint))
* SIN(RADIANS(b.lat)))) AS distance
FROM bubbles AS b, bubble_prizes AS pr, bubble_types AS bt
JOIN ( /* these are the query parameters */
SELECT ? AS latpoint, ? AS longpoint,
? AS radius, ? AS distance_unit
) AS p
WHERE b.lat
BETWEEN p.latpoint - (p.radius/p.distance_unit)
AND p.latpoint + (p.radius/p.distance_unit)
AND b.lng
BETWEEN p.longpoint - (p.radius/(p.distance_unit * COS(RADIANS(p.latpoint))))
AND p.longpoint + (p.radius/(p.distance_unit * COS(RADIANS(p.latpoint))))
AND pr.bubble = b.id
AND b.type IN ?
AND b.type = bt.type
) AS d
WHERE distance <= radius
ORDER BY distance";
然后我做
my $points = $y->dbh->prepare($sql);
$results = $points->execute($lat, $lng, $rad, $units, '(type1, type2)');
位置 '(TYPE1,TYPE2)' 应该传递给
b.type IN ?
(这是近SQL的底部)。
我已经想尽办法,我能想到的逃离这个字符串,以便它的作品(包括很多方面是清楚的疯狂,但我越来越绝望)INC
'(type1, type2)'
'\(\'type1\', \'type2\'\)'
'(\'type1\', \'type2\')'
"('type1', 'type2')"
等(我已经试过这么多的东西,我甚至不能全部记住它们。)
无论我怎么努力,我得到的形式
DBD::mysql::st execute failed: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''(type1, type2)'
AND b.type = bt.type
) AS d
WHERE distance <= radius'
的SQL错误取决于我如何试图逃脱字符串,t他的错误信息稍有不同,但总是与sql的相同部分有关。
我现在在想,转义不是我的问题,我错过了一些关于执行的东西。如果我在DB中运行代码,它可以正常使用IN语句,即b.type IN('type1','type2')正常工作。
有人能够启发我吗?我该如何做到这一点?
感谢
这样做了,谢谢 – mark