如何根据条件设置链接按钮的状态？

Question

我有2个链接按钮，它们链接到一个多视图，并根据我推动将更改活动视图。我希望它的各个视图的链接按钮显示为活动状态。

<asp:Panel runat="server" > 
 
     <div> 
 
      <asp:LinkButton ID="linkDeviceList" CommandName="SwitchViewByID" CommandArgument="viewDeviceList" runat="server" OnClick="linkDeviceList_Click" CssClass="button-link">Device List</asp:LinkButton> 
 
      <asp:LinkButton ID="linkFTPFolders" CommandName="SwitchViewByID" CommandArgument="viewFTPFolders" runat="server" OnClick="linkFTPFolders_Click" CssClass="button-link">FTP Folders</asp:LinkButton>   
 
     </div> 
 
    </asp:Panel>

的事件处理程序。我假设我会在'while'中更改按钮的状态，但无法弄清楚如何应用样式更改。

protected void linkFTPFolders_Click(object sender, EventArgs e) 
 
    { 
 
     MultiView1.SetActiveView(viewFTPFolders); 
 

 
     while (MultiView1.GetActiveView() == viewFTPFolders) 
 
     { 
 
      
 
     } 
 
    } 
 

 
    protected void linkDeviceList_Click(object sender, EventArgs e) 
 
    { 
 
     MultiView1.SetActiveView(viewDeviceList); 
 
     while (MultiView1.GetActiveView() == viewDeviceList) 
 
     { 
 
      
 
     } 
 
    }

Answer 1

我有一个类似的控制。这就是我所做的。

1. 我在点击的按钮上删除/添加了“活动”类。

2. 我禁用了被点击的按钮，因此无法再次点击 。

   protected void lbListView_Click(object sender, EventArgs e) 
       { 
        lbGridView.CssClass = "btn btn-default btn-sm pull-right dt-margin-left-5"; 
        lbGridView.Enabled = true; 
   
        lbListView.CssClass = "btn btn-default btn-sm pull-right dt-margin-left-5 active"; 
        lbListView.Enabled = false; 
   
        repGridResults.Visible = false; 
        repListResults.Visible = true; 
       } 
   
       protected void lbGridView_Click(object sender, EventArgs e) 
       { 
        lbListView.CssClass = "btn btn-default btn-sm pull-right dt-margin-left-5"; 
        lbListView.Enabled = true; 
   
        lbGridView.CssClass = "btn btn-default btn-sm pull-right dt-margin-left-5 active"; 
        lbGridView.Enabled = false; 
   
        repListResults.Visible = false; 
        repGridResults.Visible = true; 
       }