您好我有该服务拥有电子邮件和密码,并在点击提交按钮,在下面显示特定的键值对
<script>
function Puaru_Active() {
var http = new XMLHttpRequest();
var tk = document.getElementById("tk").value;
var mk = document.getElementById("mk").value;
var url = "iphone.php";
var params = "u="+tk+"&p="+mk+"";
http.open("POST", url, true);
http.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
http.onreadystatechange = function() {
if(http.readyState == 4 && http.status == 200) {
console.log(http.responseText);
}
}
http.send(params);
}
</script>
鉴于CONSOLE.LOG它puaru_Active()函数运行显示此JSON数据
形式{"session_key":"5.e3jua_TVPguaEA.1492179678.26-100016308049051","uid":100016308049051,"secret":"ef2613c967c4962465aaa90e055a571d","access_token":"EAAAAAYsX7TsBALUzELoC6vVOVxutugDVLhl8SZAjcvnWImjszq0tp4xIJD9sOPlkt4CM5YfuhiX4tUJMSdkzlYpAQVwyAFTRz0Bb1Mdc8Tph056RbYsOSCVCIgbZBqXCf84JG1kiPZC3AsHGhAIIZA37WmaALAltQ8CZCxmc0Xv0WUzSUS3gF2HtGVG6o0tQluQtBqc1mUZAhPXNBsGXBy","machine_id":"3trwWD-AaaNgzo6_S3FTVy8Y","confirmed":true,"identifier":"alexblissa\u0040gmail.com"}
现在说我只想输出access_token及其值我应该怎么做?
我曾尝试:
console.log(http.responseText.access_token)
console.log(http.responseText['access_token'])
console.log(http.access_token)
console.log(responseText.access_token)
既没有人正在谁能告诉我我该如何实现这一目标?谢谢!
什么是控制台错误?我想知道如果你需要'JSON.parse(responseText)''在通过密钥访问之前... – sweaver2112
未定义当我使用上面的方法 – Alexis
请问你可以多描述一下我该怎么做到这一点? – Alexis