2017-04-14 92 views
1

您好我有该服务拥有电子邮件和密码,并在点击提交按钮,在下面显示特定的键值对

<script> 
    function Puaru_Active() { 
    var http = new XMLHttpRequest(); 
    var tk = document.getElementById("tk").value; 
    var mk = document.getElementById("mk").value; 
    var url = "iphone.php"; 
    var params = "u="+tk+"&p="+mk+""; 
    http.open("POST", url, true); 
    http.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); 
    http.onreadystatechange = function() { 
    if(http.readyState == 4 && http.status == 200) { 
    console.log(http.responseText);   
    } 
    } 
    http.send(params); 
    } 
    </script> 

鉴于CONSOLE.LOG它puaru_Active()函数运行显示此JSON数据

形式
{"session_key":"5.e3jua_TVPguaEA.1492179678.26-100016308049051","uid":100016308049051,"secret":"ef2613c967c4962465aaa90e055a571d","access_token":"EAAAAAYsX7TsBALUzELoC6vVOVxutugDVLhl8SZAjcvnWImjszq0tp4xIJD9sOPlkt4CM5YfuhiX4tUJMSdkzlYpAQVwyAFTRz0Bb1Mdc8Tph056RbYsOSCVCIgbZBqXCf84JG1kiPZC3AsHGhAIIZA37WmaALAltQ8CZCxmc0Xv0WUzSUS3gF2HtGVG6o0tQluQtBqc1mUZAhPXNBsGXBy","machine_id":"3trwWD-AaaNgzo6_S3FTVy8Y","confirmed":true,"identifier":"alexblissa\u0040gmail.com"} 

现在说我只想输出access_token及其值我应该怎么做?

我曾尝试:

console.log(http.responseText.access_token) 
    console.log(http.responseText['access_token']) 
    console.log(http.access_token) 
    console.log(responseText.access_token) 

既没有人正在谁能告诉我我该如何实现这一目标?谢谢!

+0

什么是控制台错误?我想知道如果你需要'JSON.parse(responseText)''在通过密钥访问之前... – sweaver2112

+0

未定义当我使用上面的方法 – Alexis

+0

请问你可以多描述一下我该怎么做到这一点? – Alexis

回答

1

首先解析JSON string,然后将其作为对象进行访问。

var response = JSON.parse(http.responseText); 
console.log(response['access_token']); 
+0

谢谢安德鲁! – Alexis

0
var obj = JSON.parse(http.responseText); 
console.log(obj.access_token); 
0

您可以通过括号来做到这一点,是这样的:

var jsonStr={"session_key":"5.e3jua_TVPguaEA.1492179678.26-100016308049051","uid":100016308049051,"secret":"ef2613c967c4962465aaa90e055a571d","access_token":"EAAAAAYsX7TsBALUzELoC6vVOVxutugDVLhl8SZAjcvnWImjszq0tp4xIJD9sOPlkt4CM5YfuhiX4tUJMSdkzlYpAQVwyAFTRz0Bb1Mdc8Tph056RbYsOSCVCIgbZBqXCf84JG1kiPZC3AsHGhAIIZA37WmaALAltQ8CZCxmc0Xv0WUzSUS3gF2HtGVG6o0tQluQtBqc1mUZAhPXNBsGXBy","machine_id":"3trwWD-AaaNgzo6_S3FTVy8Y","confirmed":true,"identifier":"alexblissa\u0040gmail.com"}; 

var accessToken = jsonStr["access_token"]; 

alert(accessToken); 

工作实例here

希望它的工作!

快乐编码!

+1

jsonStr不是一个字符串,它是一个对象。 – sweaver2112