python3 pdb显示列表

Question

pdb的display命令似乎只在分配整个变量时才显示表达式。

pass 
foo = [1, 2, 3] 
foo[0] = 8 
foo.append(7) 
pass 

与python3 -m pdb bar.py运行上述代码时，然后输入我display foo得到的输出是：

> bar.py(2)<module>() 
-> foo = [1, 2, 3] 
(Pdb) display foo 
display foo: ** raised NameError: name 'foo' is not defined ** 
(Pdb) n 
> bar.py(3)<module>() 
-> foo[0] = 8 
display foo: [1, 2, 3] [old: ** raised NameError: name 'foo' is not defined **] 
(Pdb) 
> bar.py(4)<module>() 
-> foo.append(7) 
(Pdb) 
> bar.py(5)<module>() 
-> pass 
(Pdb) foo 
[8, 2, 3, 7] 
(Pdb) 

的NameError和显示器的第一输出的预期。 然而，看起来显示不出现foo更改时，其第一项改变或当我们附加7.

有没有办法告诉pdb列出这些更改？ 看来，display str(foo)做的工作，但我想知道是否有更好的解决方案。

Answer 1

是的，跟踪这些更改的方法是改为'p'命令。看到这个例子

> /home/maksim/Projects/Python/basic/test.py(2)<module>() 
-> foo = [1, 2, 3] 
(Pdb) s;;l;;p foo 
> /home/maksim/Projects/Python/basic/test.py(3)<module>() 
-> foo[0] = 8 
    1  pass 
    2  foo = [1, 2, 3] 
    3 -> foo[0] = 8 
    4  foo.append(7) 
    5  pass 
    6  
    7  
    8  
[EOF] 
[1, 2, 3] 
(Pdb) s;;l;;p foo 
> /home/maksim/Projects/Python/basic/test.py(4)<module>() 
-> foo.append(7) 
    1  pass 
    2  foo = [1, 2, 3] 
    3  foo[0] = 8 
    4 -> foo.append(7) 
    5  pass 
    6  
    7  
    8  
[EOF] 
[8, 2, 3] 
(Pdb) s;;l;;p foo 
> /home/maksim/Projects/Python/basic/test.py(5)<module>() 
-> pass 
    1  pass 
    2  foo = [1, 2, 3] 
    3  foo[0] = 8 
    4  foo.append(7) 
    5 -> pass 
    6  
    7  
    8  
[EOF] 
[8, 2, 3, 7] 
(Pdb) s;;l;;p foo 
--Return-- 
> /home/maksim/Projects/Python/basic/test.py(5)<module>()->None 
-> pass 
    1  pass 
    2  foo = [1, 2, 3] 
    3  foo[0] = 8 
    4  foo.append(7) 
    5 -> pass 
    6  
    7  
    8  
[EOF] 
[8, 2, 3, 7] 
(Pdb)