1
我有一个登录控制器,它接受用户的实例,并在登录方法中调用 正确验证用户,但问题出现在UserManager中,如果我包含构造函数以类似的方式使用mvc中的统一框架实例化Depenency注入的实现类3
public LoginController(IUser user)
{
this.user = user;
}
[httpPost]
public ActionResult Login(UserLogin model)
{
if (ModelState.IsValid)
{
// var userMgr = new UserManager();
if (user.ValidateUser(model.UserName, model.Password))
{
return RedirectToAction("Index", "Home");
}
else
{
ModelState.AddModelError("", "The user name or password provided is incorrect.");
}
// return View("UserLogin");
}
以下是其中出现问题
public class UserManager : IUser
{
IUser _user;
public UserManager(IUser user)
{
_user=user;
}
public void displayUser()
{
//.......
//.....
}
public void somefunction()
{
_user.displayUser();
}
}
原因我使用在的UserManager()构造函数是因为,因为我想用_user.displayUser()
我所做的配置在global.aspx像下面
protected void Application_Start()
{
AreaRegistration.RegisterAllAreas();
RegisterGlobalFilters(GlobalFilters.Filters);
RegisterRoutes(RouteTable.Routes);
var container = Container.InitContainer();
DependencyResolver.SetResolver(new UnityDependencyResolver(container));
}
和Container.InitContainer()调用下面类
public static class Container
{
public static IUnityContainer InitContainer()
{
var container = new UnityContainer();
// Register the relevant types for the
// container here through classes or configuration
//container.RegisterType<IUser, UserManager>(new ContainerControlledLifetimeManager());
container.RegisterType<IUser, UserManager>(new ContainerControlledLifetimeManager());
return container;
}
,我有UnityDepdendency解析器类如下
public class UnityDependencyResolver : IDependencyResolver
{
private IUnityContainer _container;
#region Ctor
public UnityDependencyResolver(IUnityContainer container)
{
_container = container;
}
#endregion
public object GetService(Type serviceType)
{
try
{
return _container.Resolve(serviceType);
}
catch (Exception ex)
{
return null;
}
}
public IEnumerable<object> GetServices(Type serviceType)
{
try
{
return _container.ResolveAll(serviceType);
}
catch (Exception ex)
{
return new List<object>();
}
}
}
所以,你有一个'UserManager'类必须被注入到自身?你甚至认为这是可能的,即使没有DI容器? – Steven 2013-03-19 12:13:26
嗨,我是新来的DI和Unity框架,并想知道如果我可以配置这样一种方式,我可以使用构造函数来设置UserManager中的实例是否有可能做到这一点?cus我不想用户UserManager userobj = new UserManager ()在UserManager类 – user2007879 2013-03-20 06:44:30
但为什么?在UserManager类中创建一个新的UserManager有什么用处。退后一步,看看设计。为什么不简单地做:'public void somefunction(){this.displayUser(); }'??? – Steven 2013-03-20 08:41:52