只有一个发生时才返回行

Question

我试图获取所有只有零的Id行。

Id | valid 
    ---| ------ 
    1 | 0 
    1 | 1 
    2 | 0 
    2 | 0 
    3 | 1 
    4 | 0 
    4 | 1 
    5 | 0 
    6 | 1 

Answer 1

SELECT ID 
FROM myTable 
WHERE Valid = 0 
    AND ID NOT IN (
     SELECT ID 
     FROM myTable 
     WHERE Valid != 0 
     ) 

Answer 2

如果您的ID具有只由零的有效这笔款项将为零。这是一个代码示例。

drop table if exists dbo.Table03; 

create table dbo.Table03 (
Id int 
, valid int 
); 

insert into dbo.Table03 (Id, valid) 
values (1, 0), (1, 1), (2, 0), (2, 0), (3, 1), (4, 0), (4, 1), (5, 0), (6, 1); 


select 
t.Id 
from dbo.Table03 t 
group by t.Id 
having SUM(t.valid) = 0 

Answer 3

您可以使用LEFT JOIN与NULL检查，以达到您预期的结果。

样品执行与给定的数据：

DECLARE @TestTable TABLE (Id int, valid int); 

INSERT INTO @TestTable (Id, valid) 
VALUES (1, 0), (1, 1), (2, 0), (2, 0), (3, 1), (4, 0), (4, 1), (5, 0), (6, 1); 

SELECT T1.* 
FROM @TestTable T1 
LEFT JOIN @TestTable T2 ON T2.Id = T1.Id AND T2.valid <> 0 
WHERE T2.Id IS NULL 

结果：

Id valid 
---------- 
2 0 
2 0 
5 0 

如果你想Id唯一的，使用SELECT DISTINCT T1.Id。

Answer 4

另一个选择

Select A.* 
From YourTable A 
Join (
     Select ID 
     From YourTable 
     Group By ID 
     Having min(valid)=0 and max(valid)=0 
     ) B 
    on A.ID=B.ID 

返回

Id valid 
2 0 
2 0 
5 0