请，我需要帮助。 如何我的数组通过PHP如何在PHP中转换数组[nesting]
Array
(
[0] => Apple
[1] => Orange
[2] => Tomato
)
转换为该
Array
(
[Apple] => Array
(
[Orange] => Array
(
[Tomato] => Array()
)
)
)
而且我不知道在我的数组有多少元素。 谢谢大家。
输出
Array
(
[0] => Apple
[1] => Orange
[2] => Tomato
[3] => Banana
[4] => Papaya
)
Array
(
[Apple] => Array
(
[Orange] => Array
(
[Tomato] => Array
(
[Banana] => Array
(
[Papaya] => Array
(
)
)
)
)
)
)
代码
$fruits = [
"Apple",
"Orange",
"Tomato",
"Banana",
"Papaya"
];
// Result Array
$result = [
$fruits[count($fruits) - 1] => []
];
// Process
for ($counter = count($fruits) - 2; $counter >= 0; $counter--) {
$temp = $result;
unset($result);
$result[$fruits[$counter]] = $temp;
}
// Display
echo "<pre>".print_r($fruits, true)."</pre>";
echo "<pre>".print_r($result, true)."</pre>";
试试这个：
$array = array('apple','orange','tomato');
$count = count($array) - 1;
$tempArray = array();
for($i = $count; $i >= 0; $i--)
{
$tempArray = array($array[$i] => $tempArray);
}
尝试用：
$target = array();
$value = array();
$path = array('apple', 'orange', 'tomato');
$rv = &$target;
foreach($path as $pk)
{
$rv = &$rv[$pk];
}
$rv = $value;
unset($rv);
print_r($target);
输出：
Array
(
[apple] => Array
(
[orange] => Array
(
[tomato] => Array
(
)
)
)
)
更新1：释
这里我使用引用/变量别名来遍历键的动态堆栈。该引用使得可以使用堆栈而不是通常更精简的递归。此外，此代码可以防止覆盖$target阵列中的现有元素。 有关引用的详细看看Reference Explained
$target = array(); //target array where we will store required out put
$value = array(); //last value i.e. blank array
$path = array('apple', 'orange', 'tomato'); //current array
$rv = &$target; //assign address of $target to $rv (reference variable)
foreach($path as $pk)
{
$rv = &$rv[$pk]; // Unused reference [ex. $rv['apple'] then $rv['apple']['orange'] .. so on ] - actually assigned to $target by reference
print_r($target);
echo '-----------------<br />';
}
$rv = $value; //here $rv have unused refernce of value tomato so finally assigned a blank array to key tomoto
//
unset($rv); // Array copy is now unaffected by above reference
echo "final array<br />";
print_r($target);
输出：
Array
(
[apple] =>
)
-----------------
Array
(
[apple] => Array
(
[orange] =>
)
)
-----------------
Array
(
[apple] => Array
(
[orange] => Array
(
[tomato] =>
)
)
)
-----------------
final array
Array
(
[apple] => Array
(
[orange] => Array
(
[tomato] => Array
(
)
)
)
)
在交代的输出，你可以跟踪的$target值在foreach环
你也可以尝试这种方式与foreach和ksort：
<?php
$fruits = array(
"Apple",
"Orange",
"Tomato",
"Banana",
"Papaya"
);
krsort($fruits);
$tmp = array();
foreach($fruits as $fruit){
$tmp = array($fruit => $tmp);
}
echo "<pre>".print_r($tmp, true)."</pre>";
?>
[概念验证]
Array
(
[Apple] => Array
(
[Orange] => Array
(
[Tomato] => Array
(
[Banana] => Array
(
[Papaya] => Array
(
)
)
)
)
)
)
谢谢，这个解决方案很棒。 – Nail
虽然环和array_pop：
$fruits = [
"Apple",
"Orange",
"Tomato",
"Banana",
"Papaya"
];
$output = [];
while ($fruit = array_pop($fruits))
{
$output = [$fruit => $output];
}
$result = array_reduce(array_reverse($fruits), function (array $acc, $fruit) {
return [$fruit => $acc];
}, []);
您只需从里面开出，敷值转换为$key => $value阵列。
有趣的问题... – Ahsan
谢谢大家。所有答案都是优越的。 – Nail
什么样的作业可以帮助完成？ ;-)。仍然有趣的问题，有趣的答案 – cypherabe