读取多个XML节点而不是一个XML问题

Question

XML账单通常有一个返回并解析的节点。我们遇到了XML账单有多个节点的问题。由于代码没有设置来处理这个问题，所以客户最终得到了一个不正确的账单。

这是代码我有去通过法案名单。如果它返回一个节点，那么它会解析xml中的信息。

var response = new List<CustomerBill>(); 
    try 
    { 
     foreach (GetBillForCAResponse eBillResponse in eBillResponseList) 
     { 
      var statementDetailsResponse = GetStatementDetails(
       new GetStatementDetailsRequest 
       { 
        BatchId = eBillResponse.BatchId, 
        CustomerAccountId = eBillResponse.CA.ToString("000000000"), 
        StatementId = eBillResponse.CAS_NUM.ToString("0000") 
       }); 

      string xmlBill = statementDetailsResponse.StatementAsXML.ToString(); 
      var document = new XmlDocument(); 
      document.LoadXml(xmlBill); 

      var saDetailedPageNode = XmlBillParser.GetDetailPageSectionBySa(requestSa, xmlBill); 
      if (saDetailedPageNode == null) continue; 

      var customerBill = new CustomerBill(); 
      customerBill.IsSurepay = XmlBillParser.GetSurepayFlagFromBill(document); 
      customerBill.ServiceAddress = XmlBillParser.GetServiceAddress(requestSa, document); 
      customerBill.monthName = XmlBillParser.GetnillStatementDate(requestSa, xmlBill); 
      customerBill.EqCurlPlanBal = XmlBillParser.getEqualizerCurrentPlanBalance(document); 
      customerBill.EqPymntDue = XmlBillParser.getEqualizerPaymentDue(document); 

      customerBill.Service = GetServiceAccountUsageAndBillingDetail(requestSa, xmlBill, saDetailedPageNode); 
      response.Add(customerBill); 
     } 
    } 
    catch (Exception ex) 
    { 
     trace.Write(new InvalidOperationException(requestSa, ex)); 
    } 
    return response; 
} 

以下是检查XML中是否存在节点的方法。我已经更改了代码，以便返回所有节点。我不得不将xmlNode类型更改为xmlNodeList，因为现在它返回了一组节点。 ****这是什么导致我在其他地方的代码的所有问题。***

public static xmlNode GetDetailPageSectionBySa(string sa, string statementXml) 
{ 
    XmlDocument document = new XmlDocument(); 
    document.LoadXml(statementXml); 
    string requestSa = sa.PadLeft(9, '0'); 
    string xpath = String.Format("//Para[IRBILGP_SA_SAA_ID_PRINT.SERVICE.ACCOUNT.STATMENT='{0}S{1}']/..", requestSa.Substring(0, 4), requestSa.Substring(4)); 
    return document.SelectNodes(xpath); 
    //var nodes = document.SelectNodes(xpath); 
    // if(nodes.Count > 0) return nodes[nodes.Count - 1]; 
    //if(!SaExistInBill(requestSa, statementXml)) return null; 
    //var node = GetDetailPageSectionByBillPrisminfoIndex(sa, statementXml); 
    //if (node != null) return node; 
    //return null; 
} 

于是久违回到它被称为..即时通讯及彼无效arguement customerBill.Service = GetServiceAccountUsageAndBillingDetail(requestSA, xmlBill, saDetailedPageNode);因为参数saDetailedPageNode现在是xmlNodeList，当它是期待xmlNode类型。如果我转到方法private static ServiceAddressBillDetail GetServiceAccountUsageAndBillingDetail(string requestSA, string xmlBill, XmlNode detailPageNode)，我在代码的末尾添加了所以您可以看到。如果我将参数XmlNode detailPageNode更改为XmlNodeList detailPageNode，我必须采取措施修复上述无效争议，那么detailPageNode.SelectNodes将变为无效，因为xmlNodeList不具有SelectNodes作为扩展方法。我通过这种方法大量使用这种扩展方法。所以我收到很多错误。

  var saDetailedPageNode = XmlBillParser.GetDetailPageSectionBySa(requestSa, xmlBill); 
      if (saDetailedPageNode == null) continue; 

      var customerBill = new CustomerBill(); 
      customerBill.IsSurepay = XmlBillParser.GetSurepayFlagFromBill(document); 
      customerBill.ServiceAddress = XmlBillParser.GetServiceAddress(requestSa, document); 
      customerBill.monthName = XmlBillParser.GetnillStatementDate(requestSa, xmlBill); 
      customerBill.EqCurlPlanBal = XmlBillParser.getEqualizerCurrentPlanBalance(document); 
      customerBill.EqPymntDue = XmlBillParser.getEqualizerPaymentDue(document); 

      customerBill.Service = GetServiceAccountUsageAndBillingDetail(requestSa, xmlBill, saDetailedPageNode); 
      response.Add(customerBill); 
     } 
    } 
    catch (Exception ex) 
    { 
     trace.Write(new InvalidOperationException(requestSa, ex)); 
    } 
    return response; 
} 
    private static ServiceAddressBillDetail GetServiceAccountUsageAndBillingDetail(string requestSA, string xmlBill, XmlNode detailPageNode) 
    { 
     var saBillDetail = new ServiceAddressBillDetail(); 
     saBillDetail.UsageServiceName = requestSA; 

     var meterReadEndXMLNodes = detailPageNode.SelectNodes("Usage_kWh_b"); 

     if (meterReadEndXMLNodes.Count == 0) 
     { 
      meterReadEndXMLNodes = detailPageNode.SelectNodes("Usage_kWh_a"); 
     } 
     if (meterReadEndXMLNodes.Count == 0) 
     { 
      meterReadEndXMLNodes = detailPageNode.SelectNodes("APSElec_kWh_b"); 
     } 
     if (meterReadEndXMLNodes.Count == 0) 
     { 
      meterReadEndXMLNodes = detailPageNode.SelectNodes("APSElec_kWh_a"); 
     } 

     var demandXMLNodes = detailPageNode.SelectNodes("Usage_kW_Total_Bold"); 

我该如何解决我的无效参数，以便我可以使用xmlNodeList而不是xmlNode？有没有办法转换或施放？或者是否有另一个可以使用的xml对象？

因为我现在正在返回多个节点。我知道我需要循环访问customerBill部分。如何在不为每个节点创建新账单的情况下做到这一点？一个xml中的所有节点都需要包含在一个账单中。

Answer 1

从您所提供的代码，这需要考虑到您的重构为XmlNodeList只有一部分是GetServiceAccountUsageAndBillingDetail()，所以你有两个选择：

1. 更新GetServiceAccountUsageAndBillingDetail()采取的XmlNodeList参数，而不是和方法内聚合值拿出最终ServiceAddressBillDetail OB JECT。
2. 环路穿过XmlNodeList您XmlNode对象和协调不同ServiceAddressBillDetail对象自己。

没有关于什么ServiceAddressBillDetail的详细信息，我只能猜测哪个更好，但我建议使用第一个选项。

private static ServiceAddressBillDetail GetServiceAccountUsageAndBillingDetail(
    string requestSA, 
    string xmlBill, 
    XmlNodeList detailPageNodes) 
{ 
    var saBillDetail = new ServiceAddressBillDetail(); 
    saBillDetail.UsageServiceName = requestSA; 

    foreach(XmlNode detailPageNode in detailPageNodes) 
    { 
     var meterReadEndXMLNodes = detailPageNode.SelectNodes("Usage_kWh_b"); 

     if (meterReadEndXMLNodes.Count == 0) 
     { 
      meterReadEndXMLNodes = detailPageNode.SelectNodes("Usage_kWh_a"); 
     } 
     if (meterReadEndXMLNodes.Count == 0) 
     { 
      meterReadEndXMLNodes = detailPageNode.SelectNodes("APSElec_kWh_b"); 
     } 
     if (meterReadEndXMLNodes.Count == 0) 
     { 
      meterReadEndXMLNodes = detailPageNode.SelectNodes("APSElec_kWh_a"); 
     } 

     var demandXMLNodes = detailPageNode.SelectNodes("Usage_kW_Total_Bold"); 
     //Whatever comes next 
    } 
} 

假设ServiceAddressBillDetail是否有“使用”，你可以简单地从每个detailPageNode添加适当的值到saBillDetail对象属性。

Answer 2

很难看到底是怎么回事，但是这可能是问题;

string xpath = String.Format("//Para.. 

“//”将在整个文档中搜索，但您可能想要搜索后代元素。

下面是一些处理类似问题的代码;

XmlNodeList staffNodes = resultXML.SelectNodes("//staff"); 
List<TempStaff> tempStaffs = staffNodes 
    .Cast<XmlNode>() 
    .Select(
     i => 
      new TempStaff() 
      { 
       StaffId = i.SelectSingleNode("id").InnerText, 
       Forename = i.SelectSingleNode("forename").InnerText, 
       Surname = i.SelectSingleNode("surname").InnerText, 
      } 
    ).ToList(); 

我的XML看起来像

<staff><forename>asdf</forename><surname>ddsf</surname><id>123</id>... </staff> 
<staff><forename>asdfas</forename><surname>asffdf</surname><id>456</id>...</staff>