在VB.NET中分割一个'十进制'

Question

我有532.016，我只想在VB.NET中得到532部分。我怎样才能做到这一点？

Answer 1

Math.Truncate(myDecimal) 

将剥去的小数部分，只留下一部分（而不是改变类型;即，这将返回该参数的类型，以及，是它Double或Decimal） 。

Answer 2

将其转换为整数。

Dim myDec As Decimal 
myDecimal = 532.016 
Dim i As Integer = Cint(myDecimal) 

'i now contains 532 

Answer 3

你可以使用System.Text.RegularExpressions：

Imports System.Text.RegularExpressions 'You need this for "Split"' 

Public Class Form1 

    Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click 

     Dim yourNumber As String = 532.016 'You could write your integer as a string or convert it to a string' 
     Dim whatYouWant() As String 'Notice the "(" and ")", these are like an array' 

     whatYouWant = Split(yourNumber, ".") 'Split by decimal' 
     MsgBox(whatYouWant(0)) 'The number you wanted is before the first decimal, so you want array "(0)", if wanted the number after the decimal the you would write "(1)"' 

    End Sub 

End Class 

Answer 4

Decimal.floor(532.016)也将返回532

Decimal.Floor回合下来到最接近的整数。

但它不适用于负数。 See this Stack Overflow question for a complete explanation

Decimal.Truncate（或Math.Truncate）真的是您的案例中的最佳选择。