短的方式在Ruby中

Question

分配几个属性相同的对象

我正在寻找一个短期的方式做到这一点：

user.first_name = "first" 
user.last_name = "last" 
user.email = "e@mail.com" 

事情是这样的：

with user: 
    first_name = "first" 
    last_name = "last" 
    email = "e@mail.com" 

是有这样的事情？

Answer 1

如果这是ActiveRecord的对象，然后：

user.assign_attributes(
    first_name: "first" 
    last_name: "last" 
    email: "e@mail.com" 
) 

Answer 2

什么block？ ActiveRecord有这么多的方法：

User.new.tap do |user| 
    user.name  = "John Doe" 
    user.username = "john.doe" 
    user.password = "john123" 
end 

或：

User.new do |user| 
    user.name  = "John Doe" 
    user.username = "john.doe" 
    user.password = "john123" 
end 

或混合的initialize：

User.new(name: "John Doe") do |user| 
    user.username = "john.doe" 
    user.password = "john123" 
end 

或超简单与update()：

user.update(
    first_name: "first" 
    last_name: "last" 
    email: "e@mail.com" 
) 

Answer 3

非ActiveRec奥德可以使用instance_eval的方法，如：

class SomeClass 
    def a(*args) 
    @a ||= args 
    end 

    def b(*args) 
    @b ||= args 
    end 
end 

2.0.0 (main):0> some_class_instance = SomeClass.new 
=> #<SomeClass:0x007f9b62b629c0> 
2.0.0 (main):0 > s = "a 'a args' 
2.0.0 (main):0 * b 'b args'" 
=> "a 'a args'\nb 'b args'" 

2.0.0 (main):0 > some_class_instance.instance_eval(s) 
=> ["b args"] 
2.0.0 (main):0 > some_class_instance.a 
=> ["a args"] 
2.0.0 (main):0 > some_class_instance.b 
=> ["b args"]