将列表加入到一个字符串中

Question

如何删除字符串的第一个单词？

0.91％ABC DEF
0.922％ABC DEF GHI

OUTPUT：ABC DEF/ABC DEF GHI

我试图

let test = str.split(separator: " ")[1...] 
print(test) 
print(test.joined(separator: " ")) 

这给了我：

["ABC", "DEF"] 
JoinedSequence<ArraySlice<Substring>>(_base: ArraySlice(["ABC", "DEF"]), _separator: ContiguousArray([" "])) 

如何将JoinedSequence打印为字符串？

Answer 1

试试这个：

let str = "0.91% ABC DEF" 
var parts = str.components(separatedBy: " ").dropFirst() 

print(parts.joined(separator: " ")) 

它打印：

“ABC DEF \ n” 个

Answer 2

给出一个字符串

let text = "0.91% ABC DEF" 

你可以搜索指数在第一个空间后

if let index = text.range(of: " ")?.upperBound { 
    let result = text.substring(from: index) 
    print(result) 
}