根据用于简单搜索的搜索词生成完整的pdf报告

Question

我在我的Django应用程序中进行了一个'简单'搜索，该搜索从数据库中生成所有匹配的列表，匹配搜索项。我希望用户能够点击一个按钮，该按钮将生成包含简单搜索中列出的所有匹配信息的pdf报告。因此，我想知道是否可以“存储”由搜索生成的查询集并将其传递给链接到“生成PDF报告”按钮的函数。

目前search.html模板：（所示的两个相关的观点）

{% extends 'base.html' %} 
{% block body %} 

{% if enzyme_list %} 
    <h1>Search Results (matching enzyme terms):</h1> 
    <ul> 
     {% for enzyme in enzyme_list %} 
      <li><a href="{% url 'gts:detail' enzyme.id %}">{{ enzyme.barcode }}, {{ enzyme.enzyme_name }}</a></li> 
     {% endfor %} 
    </ul> 
    <div> 
     <a href="{% url 'gts:pdf_report' %}" class="btn btn-primary">Generate PDF report (WORK IN PROGRESS)</a> 
    </div> 
{% else %} 
    <h1>No enzyme(s) found matching the specified search term.</h1> 
{% endif %} 

{% endblock %} 

的views.py

# The view that is used to generate the initial simplified list (template shown above) 
class EnzymeList(generic.ListView): 
    context_object_name = 'enzyme_list' 
    template_name = 'gts/search.html' 

    def get_queryset(self): 
     query = self.request.GET.get("q") 
     #queryset_list = Enzymes.objects.filter(barcode='Tt_86') 
     queryset_list = Enzymes.objects.filter(Q(barcode__icontains=query) | 
     Q(enzyme_name__icontains=query) | Q(ec_number__icontains=query) | Q(enzyme_activity__icontains=query) | 
     Q(organism__icontains=query) | Q(genbank_number__icontains=query) | Q(uniprot_accession__icontains=query) | 
     Q(description_of_activity__icontains=query) | Q(experiment_details__icontains=query) 
     ) 
     return queryset_list 

# The view that is linked to the PDF generation (just the 'framework' for now). 
def ReportView(request): 
    # Create the HttpResponse object with the appropriate PDF headers. 
    response = HttpResponse(content_type='application/pdf') 
    response['Content-Disposition'] = 'attachment; filename="somefilename.pdf"' 

    # Create the PDF object, using the response object as its "file." 
    p = canvas.Canvas(response) 

    # Draw things on the PDF. Here's where the PDF generation happens. 
    # See the ReportLab documentation for the full list of functionality. 
    p.drawString(100, 100, "Hello world.") 

    # Close the PDF object cleanly, and we're done. 
    p.showPage() 
    p.save() 
    return response 

的URL匹配功能

app_name = 'gts' 
urlpatterns = [ 
    url(r'^get_result/$', views.EnzymeList.as_view(), name='enzyme_list'), 
    url(r'^pdf_report/$', views.ReportView, name='pdf_report'), 
] 

的urls.py

我希望我能够做一些像<a href="{% url 'gts:pdf_report' enzyme_list %}" class="btn btn-primary">结合新功能头部def ReportView(request, data):在模板中，但这表示错过了反向匹配。

- 可能的解决方法 -

我找到了一种方法来得到它的工作，但我宁愿相信，这是不正确的“Django的，我刚才说了查询到的回报。因此，我可以将它发回给pdf一代。在 '蹩脚' 溶液介绍如下：

views.py

class EnzymeList(generic.ListView): 
    context_object_name = 'enzyme_list' 
    template_name = 'gts/search.html' 

    def get_queryset(self): 
     query = self.request.GET.get("q") 
     #queryset_list = Enzymes.objects.filter(barcode='Tt_86') 
     queryset_list = Enzymes.objects.filter(Q(barcode__icontains=query) | 
     Q(enzyme_name__icontains=query) | Q(ec_number__icontains=query) | Q(enzyme_activity__icontains=query) | 
     Q(organism__icontains=query) | Q(genbank_number__icontains=query) | Q(uniprot_accession__icontains=query) | 
     Q(description_of_activity__icontains=query) | Q(experiment_details__icontains=query) 
     ) 
     return (query, queryset_list) 

search.html

{% extends 'base.html' %} 
{% block body %} 

{% if enzyme_list %} 
    <h1>Search Results (matching enzyme term: "{{ enzyme_list.0 }}"):</h1> 
    <ul> 
     {% for enzyme in enzyme_list.1 %} 
      <li><a href="{% url 'gts:detail' enzyme.id %}">{{ enzyme.barcode }}, {{ enzyme.enzyme_name }}</a></li> 
     {% endfor %} 
    </ul> 
    <div> 
     <a href="{% url 'gts:pdf_report' %}?q={{enzyme_list.0}}" class="btn btn-primary">Generate PDF report (WORK IN PROGRESS)</a> 
    </div> 
{% else %} 
    <h1>No enzyme(s) found matching the specified search term: "{{ enzyme_list.0 }}".</h1> 
{% endif %} 

{% endblock % 

}

- TL：DR -

然后问题具体是如何搜索词应该是韩假设我的'修复'不是Django式的，那么可以使用ReportView函数。

Answer 1

为什么不移动查询到一个不同的功能，并随时调用它，你需要它。

def enzyme_search(query): 
    return Enzymes.objects.filter(Q(barcode__icontains=query) | 
     Q(enzyme_name__icontains=query) | Q(ec_number__icontains=query) | Q(enzyme_activity__icontains=query) | 
     Q(organism__icontains=query) | Q(genbank_number__icontains=query) | Q(uniprot_accession__icontains=query) | 
     Q(description_of_activity__icontains=query) | Q(experiment_details__icontains=query) 
    ) 

然后在EnzymeList类，

... 
def get_queryset(self): 
    query = self.request.GET.get("q") 
    return enzyme_search(query) 

def get_context_data(self): 
    context = super(EnzymeList, self).get_context_data(**kwargs) 
    context['query'] = self.request.GET.get("q") 
    return context 
... 

而且在ReportView

... 
query = self.request.GET.get("q") 
enzyme_list = enzyme_search(query) 
... 

然后在你的锚标记具有

<a href="{% url 'gts:pdf_report' %}?q={{ query }}" class="btn btn-primary"> 

这会帮助你陈德良将查询传送到ReportView。