列表查找和替换元素在另一个列表

Question

我试图做一个zip list查找和替换，使用另一个列表，但由于某种原因，我似乎无法得到我的头，而不是easy问题。所以，首先，我有一个拉链列表，它看起来像（说myzip_list）：

("this is a united string divided here","this is the value of the string),("this is a multiply string2 united here","this is the value of the string2).... 

现在

，我还有一个列表，它看起来像这样（说replace_list）：

[['united', '##sharp'], ['divided', '##blunt'], ['multiply', '##med']] 

我想要做的是将myzip_list [0]元素替换为double hash，值为replace_list。因此，作为一个最终的结果，我想直到结束：

myzip_list = ("this is a ##sharp string ##blunt here","this is the value of the string),("this is a ##med string2 ##sharp here","this is the value of the string2).... 

希望如果有人也许可以点我在正确的方向...

编辑

网络的如果replace_list只包含一个单词，下面的答案实际上是有效的。因此，例如，如果replace_list样子：

[['united all', '##sharp'], ['divided me', '##blunt'], ['multiply all', '##med']] 

如果myzip_list样子：

("this is a united all string divided me here","this is the value of the string),("this is a multiply all string2 united all here","this is the value of the string2).... 

..然后Cyber​​s方法失败。

Answer 1

l = [['united', '##sharp'], ['divided', '##blunt'], ['multiply', '##med']] 
d = dict(l) 

>>> d 
{'multiply': '##med', 'divided': '##blunt', 'united': '##sharp'} 

tups = [("this is a united string divided here","this is the value of the string"),("this is a multiply string2 united here","this is the value of the string2")] 

[[' '.join([d.get(i,i) for i in sub.split()]) for sub in tup] for tup in tups] 

输出

[['this is a ##sharp string ##blunt here', 'this is the value of the string'], 
['this is a ##med string2 ##sharp here', 'this is the value of the string2']] 

Answer 2

的zip功能是其本身的逆所以如果你有zip名单将它解压缩与本身！通过像zip(*your_list)这样的命令，然后使用下面的代码！

import re 
myzip_list="(this is a united string divided here,this is the value of the string),(this is a multiply string2 united here,this is the value of the string2)" 
tempword=[w for w in re.split('\W', myzip_list) if w] 
replace_list=[['united', '##sharp'], ['divided', '##blunt'], ['multiply', '##med']] 
my_dict=dict(replace_list) 
lst=my_dict.keys() 

for i in range(len(tempword)) : 
for j in lst: 
    if tempword[i]==j: 
     tempword[i]=my_dict[j] 

print ' '.join(tempword) 

DEMO：

"this is a ##sharp string ##blunt here this is the value of the string this is a ##med string2 ##sharp here this is the value of the string2" 

，如果你不想使用re所以更改re.split('\W', myzip_list)与my_ziplist.split()和删除impoer re。