查询数据库显示具有以下字段的上午进行记录计数和下午

Question

我有一个简单的表（walkin2012）：

ID | date | store | timestamp   | custName 
1 | 2013-05-08 | Plainfield | 2013-05-08 10:38:40 | cust1 
2 | 2013-05-08 | Plainfield | 2013-05-08 13:38:40 | cust2 
3 | 2013-05-09 | Bayport | 2013-05-09 20:38:40 | cust3 
4 | 2013-05-10 | Plainfield | 2013-05-10 17:38:40 | cust4 
5 | 2013-05-10 | Bayport | 2013-05-10 11:38:40 | cust4 

我想查询表，以显示记录的数经过10 AM-1PM为上午和什么促成的为下午每店日期，以便它只会给我这样的结果：

date  | store  | morning | afternoon 
2013-05-08 | Plainfield | 1  | 1 
2013-05-09 | Bayport | 0  | 1 
2013-05-10 | Bayport | 1  | 0 
2013-05-10 | Plainfield | 0  | 1 

我得到的日期，商店，早上上班，但我对如何困惑子查询下午的部分。这里是我的查询到目前为止：

SELECT date, store, count(walkinID) AS Morning 
FROM walkin2012 
WHERE timestamp 
BETWEEN concat_ws(' ',date,'10:00:00') AND concat_ws(' ',date,'13:00:00') 
GROUP BY date,store 

任何帮助，将不胜感激。非常感谢你。

Answer 1

SELECT date, 
     store, 
     SUM(timestamp BETWEEN date + interval 10 hour AND 
           date + interval 13 hour) Morning, 
     SUM(timestamp BETWEEN date + interval 13 hour AND 
           date + interval 24 hour) Afternoon 
FROM walkin2012 
GROUP BY date, store 

• SQLFiddle Demo

Answer 2

你可以尝试在此http://www.sqlfiddle.com

SELECT a.date, a.store, sum(Morning) as Morning, sum(afternoon) as afternoon FROM (
    SELECT date, store, count(walkinID) AS Morning , 0 AS Afternoon 
    FROM walkin2012 
    WHERE timestamp 
    BETWEEN concat_ws(' ',date,'10:00:00') AND concat_ws(' ',date,'13:00:00') 
    GROUP BY date,store 
    UNION 
    SELECT date, store, 0 AS Morning, count(walkinID) AS Afternoon 
    FROM walkin2012 
    WHERE timestamp 
    < concat_ws(' ',date,'10:00:00') OR timestamp > concat_ws(' ',date,'13:00:00') 
    GROUP BY date,store 
) a 
GROUP BY a.date, a.store