MySQL查询警告

可能重复：
mysql_fetch_array() expects parameter 1 to be resource, boolean given in select
Warning: mysql_fetch_* expects parameter 1 to be resource, boolean given error MySQL查询警告

$query = mysql_query("SELECT MAX(id) from test"); 
$result = mysql_query($q); 
$data = mysql_fetch_array($result); 
$start = $data[0]; 
$end = $start -15; 
$query = mysql_query("SELECT * from test 
     WHERE id = BETWEEN '".$start."' AND '".$end."' ORDER BY id DESC");

谁能告诉我为什么我收到这个错误？

警告：mysql_fetch_array（）预计参数1是资源，鉴于布尔

通常是警告说，提供的参数不是一种资源。正确？

来源

2011-02-01 awmayhall

您的查询中可能有错误。这导致`$ result`为`false`。使用`echo mysql_error（）`输出它。 – 2011-02-01 23:21:11

`$ q`不在您发布的示例中 - 您的查询都在`$ query`变量中。 – 2011-02-01 23:22:26

我认为，问题是，你说的

"WHERE id = BETWEEN '".$start."' AND '".$end."'"

我不认为应该有BETWEEN operator之前=。这将是一个语法错误，所以你不会得到结果集。

来源

2011-02-01 23:34:02

你认为是正确的+1 – Endophage 2011-02-02 00:27:20

试试这个

$query = mysql_query("SELECT MAX(id) from test"); 
$result = mysql_query($query); 
$data = mysql_fetch_array($result); 
$start = $data[0]; 
$end = $start -15; 
$query = mysql_query("SELECT * from test 
    WHERE id BETWEEN '".$start."' AND '".$end."' ORDER BY id DESC");

来源

2011-02-01 23:37:32 borayeris

$query = mysql_query("SELECT MAX(id) from test"); 
$result = mysql_query($q); //you don't have variable $q in this code, you mean $query 
$data = mysql_fetch_array($result); //script tell's that $result is false 
$start = $data[0]; //don't have eather 
$end = $start -15; 
$query = mysql_query("SELECT * from test 
    WHERE id = BETWEEN '".$start."' AND '".$end."' ORDER BY id DESC"); 
    //and you must write id BETWEEN, not id = BETWEEN

来源

2011-02-01 23:38:05 MDI

好了，所以我得到了它的工作。代码如下...

$q = mysql_query("SELECT MAX(id) FROM test"); 
    $data = mysql_fetch_array($q); 
    $start = $data[0]; 

    //only shows 15 articles at a time 
    if($start>16) 
    { 
     $end = $start -15; 
    } 

    else 
    { 
     //Sets the minimum id to 1 
     $start = 1; 
    } 

    $query = mysql_query("SELECT * from test WHERE id BETWEEN '".$end."' AND '".$start."' ORDER BY id DESC");

对于一个$查询需要$ q，并且我的$ start和$ end需要切换。感谢您为所有人提供帮助！

来源

2011-02-02 03:37:07 awmayhall

MySQL查询警告

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