ApplicationDelegate在这里没有做自己的工作！谁能帮我？

Question

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { 
    MaSystemGuiAppDelegate *appDelegate = (MaSystemGuiAppDelegate *)[[UIApplication sharedApplication] delegate]; 

    appDelegate.deneme = [tableData objectAtIndex:indexPath.row] ; 
    NSLog(@"my row", appDelegate.deneme); // THIS IS NOT PRINTING** 
    NSLog(@"my row = %@", [tableData objectAtIndex:indexPath.row]); //THIS IS PRINTING THE VALUE ON CONSOLE** 
    NSInteger row = [indexPath row]; 
    if(self.searchDetailViewController == nil){ 
     SearchDetailViewController *asearchDetail = [[SearchDetailViewController alloc] initWithNibName:@"SearchDetailView" bundle:nil]; 
     self.searchDetailViewController = asearchDetail; 
     [asearchDetail release]; 
} 
    searchDetailViewController.title = [NSString stringWithFormat:@"%@", [searchArray objectAtIndex:row]]; 
    MaSystemGuiAppDelegate *delegate = [[UIApplication sharedApplication] delegate]; 
    [delegate.searchNavController pushViewController:searchDetailViewController animated:YES]; 
} 

deneme是在MaSystemGuiAppDelegate.h中声明的NSMutableArray。它在MaSystemGuiAppDelegate.m的applicationDidFinishLaunching方法中被安装为：[[NSMutableArray alloc]init];。

在上面的代码中，[tableData objectAtIndex:indexPath.row]正在检索tableview上触及的其中一个值。当我把这个值放在deneme（正如你在代码中看到的那样）时，没有任何东西被打印。

我错过了什么？

Answer 1

试试这个：

的NSLog（@ “我行：％@”，appDelegate.deneme）;

您需要告诉NSLog您想要打印传递给它的参数以及这些参数的格式是什么。