我有来自Spring项目的web.xml和applicationContext.xml。 我想改变这一点,只获得我的项目的Java配置,但我不知道如何。Spring - 从xml到Java配置
网络的XML
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>Spring + JAX-WS</display-name>
<servlet>
<servlet-name>jaxws-servlet</servlet-name>
<servlet-class>
com.sun.xml.ws.transport.http.servlet.WSSpringServlet
</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>jaxws-servlet</servlet-name>
<url-pattern>/hello</url-pattern>
</servlet-mapping>
<!-- Register Spring Listener -->
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
</web-app>
的applicationContext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:ws="http://jax-ws.dev.java.net/spring/core"
xmlns:wss="http://jax-ws.dev.java.net/spring/servlet"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://jax-ws.dev.java.net/spring/core
http://jax-ws.dev.java.net/spring/core.xsd
http://jax-ws.dev.java.net/spring/servlet
http://jax-ws.dev.java.net/spring/servlet.xsd"
>
<wss:binding url="/hello">
<wss:service>
<ws:service bean="#helloWs"/>
</wss:service>
</wss:binding>
<!-- Web service methods -->
<bean id="helloWs" class="it.capgemini.HelloWorldWS">
<property name="helloWorldBo" ref="HelloWorldBo" />
</bean>
<bean id="HelloWorldBo" class="it.capgemini.soap.HelloWorlBoImpl" />
</beans>
感谢您的建议!
的可能的复制[Spring配置文件(http://stackoverflow.com/questions/6283653/spring-configuration) – Dez
希望在http://stackoverflow.com/questions/39851336/spring-utilizing-mongo-implementation-over-jpa/39852442#39852442帮助编辑。 – HARDI