我在我的数据库中的这些(简体)表休眠例外:重复的条目键“主要”
我与这些(简体)两个类映射表
公司
@Entity
public class Company {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String name;
@OneToMany(fetch = FetchType.LAZY, cascade = CascadeType.PERSIST)
@JoinTable(name="company_employee",
joinColumns={@JoinColumn(name="company_id")},
inverseJoinColumns={@JoinColumn(name="employee_id")})
@OrderBy("name ASC")
private SortedSet<Employee> employees = new TreeSet<Employee>();
// contructors + getters + setters
}
EMPLOYEE
@Entity
public class Employee implements Comparable<Employee> {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String name;
@OneToOne(fetch = FetchType.LAZY, optional = true)
@JoinTable(name="company_employee",
joinColumns={@JoinColumn(name="employee_id")},
inverseJoinColumns={@JoinColumn(name="company_id")}
)
private Company company;
@Override
public int compareTo(Employee anotherEmployee) {
return this.name.compareTo(anotherEmployee.name);
}
// contructors + getters + setters + equals + hashcode
}
我使用的员工SortedSet/TreeSet
在Company
定义为获得按名称排序的员工。
当我坚持对象时会出现问题。我读过你必须在双方建立关系。在坚持公司之前,我将公司中的员工和公司中的员工设置在员工中。当我尝试执行坚持时,我将获得以下例外
Exception in thread "main" javax.persistence.RollbackException: Error while committing the transaction
at org.hibernate.jpa.internal.TransactionImpl.commit(TransactionImpl.java:86)
at es.rubioric.hibernate.MainTest.main(MainTest.java:43)
Caused by: javax.persistence.PersistenceException: org.hibernate.exception.ConstraintViolationException: could not execute statement
at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1692)
at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1602)
at org.hibernate.jpa.internal.TransactionImpl.commit(TransactionImpl.java:67)
... 1 more
Caused by: org.hibernate.exception.ConstraintViolationException: could not execute statement
at org.hibernate.exception.internal.SQLExceptionTypeDelegate.convert(SQLExceptionTypeDelegate.java:59)
at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:42)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:109)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:95)
at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.executeUpdate(ResultSetReturnImpl.java:207)
at org.hibernate.engine.jdbc.batch.internal.NonBatchingBatch.addToBatch(NonBatchingBatch.java:45)
at org.hibernate.persister.collection.AbstractCollectionPersister.recreate(AbstractCollectionPersister.java:1314)
at org.hibernate.action.internal.CollectionRecreateAction.execute(CollectionRecreateAction.java:50)
at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:447)
at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:333)
at org.hibernate.event.internal.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:335)
at org.hibernate.event.internal.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:39)
at org.hibernate.internal.SessionImpl.flush(SessionImpl.java:1224)
at org.hibernate.internal.SessionImpl.managedFlush(SessionImpl.java:464)
at org.hibernate.internal.SessionImpl.flushBeforeTransactionCompletion(SessionImpl.java:2890)
at org.hibernate.internal.SessionImpl.beforeTransactionCompletion(SessionImpl.java:2266)
at org.hibernate.engine.jdbc.internal.JdbcCoordinatorImpl.beforeTransactionCompletion(JdbcCoordinatorImpl.java:485)
at org.hibernate.resource.transaction.backend.jdbc.internal.JdbcResourceLocalTransactionCoordinatorImpl.beforeCompletionCallback(JdbcResourceLocalTransactionCoordinatorImpl.java:146)
at org.hibernate.resource.transaction.backend.jdbc.internal.JdbcResourceLocalTransactionCoordinatorImpl.access$100(JdbcResourceLocalTransactionCoordinatorImpl.java:38)
at org.hibernate.resource.transaction.backend.jdbc.internal.JdbcResourceLocalTransactionCoordinatorImpl$TransactionDriverControlImpl.commit(JdbcResourceLocalTransactionCoordinatorImpl.java:230)
at org.hibernate.engine.transaction.internal.TransactionImpl.commit(TransactionImpl.java:65)
at org.hibernate.jpa.internal.TransactionImpl.commit(TransactionImpl.java:61)
... 1 more
Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLIntegrityConstraintViolationException: Duplicate entry '32-80' for key 'PRIMARY'
at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
at sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source)
at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source)
at java.lang.reflect.Constructor.newInstance(Unknown Source)
at com.mysql.jdbc.Util.handleNewInstance(Util.java:406)
at com.mysql.jdbc.Util.getInstance(Util.java:381)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1015)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:956)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3558)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3490)
at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1959)
at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2109)
at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2643)
at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:2077)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2362)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2280)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2265)
at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.executeUpdate(ResultSetReturnImpl.java:204)
... 18 more
这是生成该异常的简化代码。 [编辑者@NicolasFilotto评论后提交位置]
public static void main(String[] args) throws ParseException {
EntityManagerFactory emf = Persistence.createEntityManagerFactory("TestDB");
EntityManager em = emf.createEntityManager();
EntityTransaction tx = em.getTransaction();
tx.begin();
try {
Company c = new Company("Nike");
Employee e1 = new Employee("Anthony");
e1.setCompany(c); // line 26
Employee e2 = new Employee("Zenobia");
e2.setCompany(c); // line 28
Employee e3 = new Employee("Chuck");
e3.setCompany(c); // line 30
Employee e4 = new Employee("Bernard");
e4.setCompany(c); // line 32
c.getEmployees().add(e1);
c.getEmployees().add(e2);
c.getEmployees().add(e3);
c.getEmployees().add(e4);
em.persist(c);
tx.commit();
} finally {
em.close();
}
}
这些是由Hibernate内部执行的SQL语句。
Hibernate: insert into Company (name) values (?)
Hibernate: insert into Employee (name) values (?)
Hibernate: insert into company_employee (company_id, employee_id) values (?, ?)
Hibernate: insert into Employee (name) values (?)
Hibernate: insert into company_employee (company_id, employee_id) values (?, ?)
Hibernate: insert into Employee (name) values (?)
Hibernate: insert into company_employee (company_id, employee_id) values (?, ?)
Hibernate: insert into Employee (name) values (?)
Hibernate: insert into company_employee (company_id, employee_id) values (?, ?)
Hibernate: insert into company_employee (company_id, employee_id) values (?, ?)
如果我评论第26,28,30和32行(上面标记),相同的代码完美地工作。但我想知道为什么会生成这个异常。为什么重复键?
在此先感谢。
尝试添加坚持(c);在Employee e1之前.. –
注意:我不认为在finally块中调用tx.commit()是个好主意 –
@NicolasFilotto得到相同的异常。为什么在finally块中放置提交不是一个好主意? – RubioRic