我有一个应用程序,需要一个摄像头图像,并在位图上放置鱼眼失真效果。大约需要20多秒才能应用效果并重新绘制位图。我决定实现一个处理程序来加速第二个线程中的处理。处理程序代码似乎对应用程序没有影响。基本上,当滑动条被用户移动时,这会使位图变形得更多。 sldebar移动和重绘()之间存在显着的延迟。我是否正确地使用了这个?谢谢马特。处理程序没有加速在辅助线程中的应用程序
public class TouchView extends View{
private File tempFile;
private byte[] imageArray;
private Bitmap bgr;
private Bitmap bm;
private Bitmap bgr2 = null;;
private Paint pTouch;
private int centreX = 1;
private int centreY = 1;
private int radius = 50;
private int Progress;
private static final String TAG = "*********TouchView";
private Filters f = null;
private Handler handler = new Handler() {
@Override
public void handleMessage(Message msg) {
super.handleMessage(msg);
}
};
public TouchView(Context context) {
super(context);
// TouchView(context, null);
}
public TouchView(Context context, AttributeSet attr) {
super(context,attr);
//......code that loads bitmap from sdcard
BitmapFactory.Options bfo = new BitmapFactory.Options();
bfo.inSampleSize = 1;
bm = BitmapFactory.decodeByteArray(imageArray, 0, imageArray.length, bfo);
bgr = Bitmap.createBitmap(bm.getWidth(), bm.getHeight(), bm.getConfig());
bgr = bm.copy(bm.getConfig(), true);
bgr2 = Bitmap.createBitmap(bm.getWidth(), bm.getHeight(), bm.getConfig());
f = new Filters();
}// end of touchView constructor
public void findCirclePixels(){
Log.e(TAG, "inside fcp()");
float prog = (float)Progress/150000;
bgr2 = f.barrel(bgr,prog);
}// end of changePixel()
@Override
public boolean onTouchEvent(MotionEvent ev) {
switch (ev.getAction()) {
case MotionEvent.ACTION_DOWN: {
centreX = (int) ev.getX();
centreY = (int) ev.getY();
findCirclePixels();
invalidate();
break;
}
case MotionEvent.ACTION_MOVE: {
centreX = (int) ev.getX();
centreY = (int) ev.getY();
findCirclePixels();
invalidate();
break;
}
case MotionEvent.ACTION_UP:
break;
}
return true;
}//end of onTouchEvent
public void initSlider(final HorizontalSlider slider)
{
Log.e(TAG, "******setting up slider*********** ");
slider.setOnProgressChangeListener(changeListener);
}
private OnProgressChangeListener changeListener = new OnProgressChangeListener() {
@Override
public void onProgressChanged(View v, int progress) {
// TODO Auto-generated method stub
setProgress(progress);
processThread();
Log.e(TAG, "***********progress = "+Progress);
}
};
private void processThread() {
new Thread() {
public void run() {
Log.e(TAG, "about to call findcirclepixel in new thread");
findCirclePixels();
handler.sendEmptyMessage(0);
}
}.start();
}
@Override
public void onDraw(Canvas canvas){
super.onDraw(canvas);
canvas.drawBitmap(bgr2, 0, 0, null);
}//end of onDraw
protected void setProgress(int progress2) {
this.Progress = progress2;
findCirclePixels();
invalidate();
}
}
维亚斯我记得现在阅读,谢谢。我试过看AsyncTask,但不知道如何将它应用到我的应用程序。我会发表另一个问题。 – turtleboy 2011-06-08 19:13:15