Bind_param非对象错误W/mysqli的

Question

当试图插入初始行的表，将跟踪每天的意见，我收到错误：

Fatal error: Call to a member function bind_param() on a non-object in /.../functions.php on line 157

这条线是最后下面的一组：

if($stats_found) { 
$sqlquery = "UPDATE vid_stats SET views = ? WHERE title = ? AND format = ? AND date = ? AND results = ?"; 
$views++; 
} else { 
$sqlquery = "INSERT INTO vid_stats (views, title, format, results) values (?, ?, ?, ?)"; 
$views = 1; 
} 

$stmt = $mysqli->prepare($sqlquery); 
/* bind parameters for markers */ 
$stmt->bind_param("dsss", $views, $title, $format, "success"); 

有关该问题的任何提示？

---

万一它与周围的代码的问题，下面是完整的功能：

function updateViewCount($title, $format, $results) { 
//update view count 
global $mysqli; 
$views = 0; 
if ($stmt = $mysqli->prepare("SELECT views FROM vid_stats WHERE title = ? AND format = ? AND date = ?")) { 

    /* bind parameters for markers */ 
    $stmt->bind_param("ssd", $title, $format, date("Y-m-d")); 

    /* execute query */ 
    $stmt->execute(); 

    /* bind result variables */ 
    $stmt->bind_result($views); 

    /* fetch value */ 
    if ($stmt->fetch()) { 
    $stats_found = true; 
    } else { $stats_found = false; } 

    /* close statement */ 
    $stmt->close(); 

    if($stats_found) { 
    $sqlquery = "UPDATE vid_stats SET views = ? WHERE title = ? AND format = ? AND date = ? AND results = ?"; 
    $views++; 
    } else { 
    $sqlquery = "INSERT INTO vid_stats (views, title, format, results) values (?, ?, ?, ?)"; 
    $views = 1; 
    } 

    $stmt = $mysqli->prepare($sqlquery); 
    /* bind parameters for markers */ 
    echo $sqlquery."<br>".$views."<br>".$title."<br>".$format; 
    $stmt->bind_param("dsss", $views, $title, $format, "success"); 

    /* execute query */ 
    $stmt->execute(); 

    /* close statement */ 
    $stmt->close(); 
} 
} 

Answer 1

的问题是用户错误：我有result列错误的名称。

当我在行$stmt = $mysqli->prepare($sqlquery);后面添加echo $mysqli->error;时发现了列名错误，这是发现的。