2017-12-03 304 views
0

我有一个代码为我的计算器添加千位分隔符,自动(SWIFT)

我怎么可以这样做,当用户将输入他将自动空格隔开的数字?

我一直在试图寻找了很久的答案,但没有适合它被显示马上


gif

var currentInput: Double { 
    get { 
     return Double (displayResultLabel.text!)! 
    } 
    set { 
     let value = "\(newValue)" 
     let ValueArray = (value.components(separatedBy:".")) 
     if ValueArray[1] == "0" { 
      displayResultLabel.text = "\(ValueArray[0])" 
     } else { 
      displayResultLabel.text = "\(newValue)" 
     } 
     stillTyping = false 
    } 
} 
@IBAction func numberPressed(_ sender: UIButton) { 
    let number = sender.currentTitle! 

    if stillTyping { 
     if (displayResultLabel.text?.characters.count)! < 14 { 
      displayResultLabel.text = displayResultLabel.text! + number 
     } 
    } else { 
     displayResultLabel.text = number 
     stillTyping = true 
    } 
} 

然后发生了什么:

@IBAction func numberPressed(_ sender: UIButton) { 
    let number = sender.currentTitle! 

    if stillTyping { 
     if (displayResultLabel.text?.characters.count)! < 14 { 
      let formatter = NumberFormatter() 
      formatter.numberStyle = .decimal 
      let newNumber = NSNumber(value: Double(displayResultLabel.text! + number)!) 

      displayResultLabel.text = formatter.string(from: newNumber) 
     } 
    } else { 
     displayResultLabel.text = number 
     stillTyping = true 
    } 
} 

错误 enter image description here

var stillTyping = false 
var dotIsPlaced = false 
var firstOperand: Double = 0 
var secondOperand: Double = 0 
var operationSign: String = "" 

回答

1

最好将您的值累加到单独的字符串中,该字符串没有应用格式化而不是使用文本字段作为数据模型。然后可格式化十进制和根据需要使用在标签显示它一个NumberFormatter:出现

let formatter: NumberFormatter = { 
    let formatter = NumberFormatter() 
    formatter.numberStyle = .decimal 
    return formatter 
}() 

var currentInput: String = "0" { 
    didSet { 
     self.displayResultLabel?.text = self.currentDisplay 
} 

var currentValue: Double { 
    return Double(self.currentInput) ?? 0 
} 

var currentDisplay: String { 
    return formatter.string(from: NSNumber(value:self.currentValue)) ?? "0" 
} 

func addDigit(_ digit: Int) { 
    if currentInput.count < 14 { 
     let newValue = self.currentValue * 10 + Double(digit) 
     self.currentInput = "\(newValue)" 
    } 
} 

@IBAction func numberPressed(_ sender: UIButton) { 
    guard let digit = Int(sender.currentTitle!) else { 
     return 
    } 

    self.addDigit(digit) 
} 
1

这是NumberFormatter s为用于

let formatter = NumberFormatter() 
formatter.numberStyle = .decimal 
if let newNumber = formatter.number(from: displayResultLabel.text! + number){ 
    displayResultLabel.text = formatter.string(from: newNumber) 
} 

注意NumberFormatter走吧两种方式,你可以(并且可能应该)用它来从分析数字字符串也是

+0

错误 - 不能在类型使用实例成员“numberStyle”“的NumberFormatter” – B2Fq

+0

很抱歉,。我忘了parens来实际实例化它:P现在在我的机器上编译一个类似的例子 –

+0

他开始输入8888(它变成888 8)并且出现错误 - “线程1:致命错误:意外地发现零,而解包一个可选的“ – B2Fq