获取属性python

Question

class A(object): 
     a = 1 
     b = 0 
     c = None 
     d = None 
a_obj=A() 
a_list = ['a', 'b', 'c', 'd'] 
attrs_present = filter(lambda x: getattr(a_obj, x), a_list) 

我想要a和b两个属性，这里0是一个有效的值。我不想使用比较== 0

有没有办法得到那些？ 任何帮助将appriciated，谢谢。

Answer 1

如果你想排除c，d（None S），使用is None或is not None：

attrs_present = filter(lambda x: getattr(a_obj, x, None) is not None, a_list) 
# NOTE: Added the third argument `None` 
#  to prevent `AttributeError` in case of missing attribute 
#  (for example, a_list = ['a', 'e']) 

如果你想包括c，d，使用hasattr：

attrs_present = filter(lambda x: hasattr(a_obj, x), a_list)