如何在PHP

Question

串（16）转换为INT（1）例如

<div ng-repeat = 'list in lists'> 

<?php 

$user_post_id = "{{list.user.id}}";   //this syntax works 
var_dump($user_post_id);      // gives String(16) '1'  
$user_post_int_id = (int)$user_post_id;  // change from string to int 
var_dump($user_post_int_id);     // gives int(1) 0, I don't know why isn't type conversion working! 

echo $user_post_id;       // echoes out 1 
echo $user_post_int_id;      //echoes out the 0 

所以，我认为主要的问题是转换的类型，因为我想一两件事，其中字符串（1）转换到int（1）没有问题，但用字符串（16），所有东西都吹散，结果为0.

Answer 1

我有3建议4U（我的服务器上的所有工作正常）

为原有我的评语：

<div ng-repeat = 'list in lists'> 

<?php 

$user_post_id = "{{list.user.id}}";   //this syntax works 
var_dump($user_post_id);      // gives String(16) '1'  
$user_post_int_id = (int)$user_post_id;  // change to int 
var_dump($user_post_int_id);     
// gives int(1) 1, is not test your php/server conf! 

echo $user_post_id;       // echoes out 1 
echo $user_post_int_id;      //echoes out 1 

那我劝你尝试使用您的代码，在您的服务器上运行更改：

1. 替换$ user_post_id =“{{list.user.id}}”; 到$ user_post_id =（int）{{list.user.id}}; //希望你的php wudn't显示错误

2. 更换$ user_post_int_id =（INT）$ user_post_id; 到$ user_post_int_id = floor（（int）$ user_post_id）; 或$ user_post_int_id = ceil（（int）$ user_post_id）;

3. 替换$ user_post_id =“{{list.user.id}}”; 到$ user_post_id =（int）（{{list.user.id}}）+ 1; 或加零，这些破解有时候适合我！

p.s. （int）可以跟你做一个诡计，php可以使用十六进制bin或其他的smthth。重新测试两次！ php.net/manual/en/language.types.integer.php php.net/manual/en/language.types.type-juggling.php

Answer 2

不能在服务器端语句内使用Angular表达式，因为在运行所有服务器逻辑之后，Angular语句在客户端运行。

在您的代码：

<div ng-repeat = 'list in lists'> 

<?php 

$user_post_id = "{{list.user.id}}"   //list.user.id is a JS variable, you cannot use it in PHP. 
$user_post_int_id = (int)$user_post_id;  // something wrong here, you do not need this step, normally if you retrieved the code from server side. 

{{ $user_post_int_id }}      //this should not work 

But still this blade function fails 

@if(Auth::user()->id == $user_post_int_id) 
do something //returns false, makes alot of sense, as again you are trying to get variables from JS and passing them to PHP scripts. This will never work. 
@endif