添加链接到SQLFORM.grid，Web2PY

Question

def index(): 
gridHome = SQLFORM.grid(db.games, editable=False, create=False, csv=False, deletable=False, details=False, 
links = [lambda row: A('View Post',_href=URL("default","show",args=[row.id]))]) 
return locals() 

我想添加另一个链接到SQL网格就像上面的一个。我不断收到语法错误，因为我不知道如何写出来。

'Review',_href=URL("default","review",args=[row.id] 

这是我想要添加的链接。

Answer 1

您的联系右括号之前，关闭全球阵列

def index(): 
    gridHome = SQLFORM.grid(db.games, editable=False, create=False, csv=False, deletable=False, details=False, 
          links = [lambda row: A('View Post',_href=URL("default","show",args=[row.id])), 
            lambda row: A('Review',_href=URL("default","review",args=[row.id]))])  

    return locals()