2012-08-17 87 views
1

我试图确保某些字段在我的表单中不留空白。它似乎很简单,但由于某种原因,它不起作用。警报没有显示,并返回false不起作用(它继续发布到我的数据库空白条目)请帮助,我做错了什么。谢谢!Javascript返回false,警告不起作用

脚本:

function check(){ 
var name = getElementById('name'); 
var date = getElementById('date'); 
var pri = getElementById('pri'); 
var asapc = getElementById('asapc'); 
var asapn = getElementById('asapn'); 
var obr = getElementById('obr'); 
var obc = getElementById('obc'); 
var obn = getElementById('obn'); 
    if (name.value == "" || date.value == "" || pri.value == "not" || asapc.value == "" || asapn.value == "" || obr.value == "" || obc.value == "" || obn.value == "") { 
    alert("One or more fields were not filled out."); 
    return false ; } 
    return true; 
} 

代码:

<FORM ACTION="step2.php" METHOD="POST" onsubmit="check();"> 
<!-- fields here --> 
<INPUT TYPE="submit" VALUE="CONTINUE"> 

回答

5

访问每一个元素document.getElementById...和形式的标签写入该onsubmit="return check();"代替如果onsubmit="check();"

2

你缺少回报的位置:

<FORM ACTION="step2.php" METHOD="POST" onsubmit="return check();"> 
+0

假设一个领域是空白,切忌警报仍火? – j08691 2012-08-17 16:51:40

0

你缺少(文件),这是正确的语法:

document.getElementById('id'); 


<script> 
function check() { 
var name = document.getElementById('name'); 
var date = document.getElementById('date'); 
    if (name.value == "" || date.value == "") { 
     alert("One or more fields were not filled out."); 
     return false; 
    } 
} 
</script> 

和手段的getElementById通过ID不是我的标签名

<FORM ACTION="step2.php" METHOD="POST" onsubmit="return check();"> 
    <input name="name" type="text" value="" id="name"> 
    <input name="date" type="text" value="" id="date"> 
    .....etc.. 
    <INPUT TYPE="submit" VALUE="CONTINUE"> 
</FORM>