将具有unix时间戳的CSV文件拆分为7个不同的csv文件

Question

我有一个大的2列csv文件（“data.csv”）与数周的数据。 列一个Unix的时间戳 列中有两个具有字符串：

1329548400,cats 
1329548400,dogs 
1329550200,fish 
1329550200,cats 
1329552000,dogs 
1329552000,fish 
1329584400,cats 
1329584400,dogs 
1329550200,cats 

通过PHP，我需要data.csv转换为7个档，Sunday.csv，Monday.csv ... Saturday.csv

如果我能抓住每一行，我知道我可以做这样的事情

$temp = "data.csv"; 
$fileName = array_unique($temp); 
foreach ($fileName as $row) { 
    $theDay = date("Y", $row[firstcolumn]); 
    if ($theDay == "Sunday") { 
     $fileToWriteTo = "Sunday.csv"; 
     $f = fopen($fileToWriteTo, "a"); 
     fwrite($fileToWriteTo, $row . "\n"); 
     fclose($fileToWriteTo); 
     } 
    if ($theDay == "Monday") { 
     $fileToWriteTo = "Monday.csv"; 
     $f = fopen($fileToWriteTo, "a"); 
     fwrite($fileToWriteTo, $row . "\n"); 
     fclose($fileToWriteTo); 
     } 
    } 

问题是

1）我不知道如何读DA的每一行ta.csv，假设上面的语法是错误的 2）我承认我的一个PHP门外汉:)

...我有多远？我甚至在大球场？

Answer 1

首先，在每次迭代时不要open file在循环之前做。现在

$fps = array(); // fps = File Pointers 
$days = array('Sunday', 'Monday', 'Tuesday', ...); 
foreach($days as $key => $name){ 
    $fps[ $name] = fopen('a', $name . '.csv'); 
    if(!$fps[ $name]){ 
     die("Cannot open $name.csv"); 
    } 

    // Although I wouldn't rely on date's `l` format, because 
    // it can be localized and script may just stop working 
    // and rather use: 
    $fps[ $key] = fopen('a', $name . '.csv'); 
    if($fps[ $key])... 
    // Sunday = 7 = 0, Monday = 1... 
} 

，你会通过date('w')地址字段，这将给数字0 - 周日，6 - 星期六：

$day = date('w', $timestamp); 

关于制作独特的结果...你可能需要使用功能如in_array()，并将所有处理过的行存储在一个数组中。

关于读取和写入CSV文件，有2个功能：fgetcsv() resp。 fputcsv()。所以整个循环：

$temp = "data.csv"; 
$rows = array(); // List of unique itemps 
$fp = fopen($temp, 'r') or die("Cannot open `$temp` for reading"); 
// Put here loop which will open all 7 files as mentioned above 
// Optionally skip first row (it may contain header) 
fgets($fp); 

// Read each row 
while(($array = fgetcsv($fp, 10000, ',', '"') !== false){ 
    // Check unique row 
    $row = implode(',', $array); 
    if(in_array($row, $rows)){ 
     continue; // Skip this iteration 
    } 
    $rows[] = $row; 

    $day = date('w', $array[0]); 
    fputcsv($fps[$day], $array); 
} 

而且不要忘了close所有文件：

fclose($fp); 
foreach($fps as $fp){ 
    fclose($fp); 
} 

的

Answer 2

如果您正在从文件中读取数据，则需要创建一个句柄来读取该文件，然后获取每行并进行解析。

$handle = fopen('data.csv','r'); 
while($line = fgets($handle)){ 
    //Do any parsing here. 
    $array = explode(',',$line); 
    $timestamp = $array[0]; 
    $string = $array[1]; 
    //Do whatever else you need to do with it. 
} 

如果您想从一个文件创建更多文件，请尝试阅读本文。

http://php.net/manual/en/function.fopen.php

Answer 3

也许这将做的工作。我没有测试过它。

$temp = "data.csv"; 
$fileData = file($temp); 
$errors = 0; 
$days = Array(fopen('Sunday.csv','a+'), 
       fopen('Monday.csv','a+'), 
       fopen('Tuesday.csv','a+'), 
       fopen('Wednesday.csv','a+'), 
       fopen('Thursday.csv','a+'), 
       fopen('Friday.csv','a+'), 
       fopen('Saturday.csv','a+')); 
foreach($days as $fd) $errors += ($fd === FALSE); 
if(! $errors) 
{ 
    foreach ($fileData as $row) { 
     $columns=explode(',',$row); 
     $theDay = date("w", $columns[0]); 
     if(empty($days[$theDay])) continue; // maybe not valid date 
     fwrite($days[$theDay], $row."\n"); 
    } 
} 
else 
{ 
    echo "I couldn't open $errors of the files\n"; 
} 
foreach($days as $fd) if($fd !== FALSE) fclose($fd);