2016-11-22 106 views
0

我有下列数据的表:SQL服务器调换查询结果

ItemId PendingTime 
1  2016-11-23 15:57:56.000 
2  2016-07-09 17:33:09.000 
3  2015-11-27 18:34:03.000 

等..

我想知道自去年30分钟挂起项目的总和,去年1小时,最近1周,最近1个月和超过一年。我想出了以下查询:

SELECT 
    SUM(CASE 
      WHEN datediff(MINUTE, PENDING_TIME,GETDATE()) <= 30 
       THEN 1 ELSE 0 
     END) AS '30 Min', 
Sum(case when (datediff(MINUTE,PENDING_TIME, GETDATE())) > 30 AND (datediff(MINUTE,PENDING_TIME, GETDATE())) <= 60 then 1 Else 0 End) as 'Over 30 Min', 
Sum(case when (datediff(MINUTE,PENDING_TIME, GETDATE())) > 60 AND (datediff(HOUR,PENDING_TIME, GETDATE())) <= 24 then 1 Else 0 End) as 'Over 1 Hr', 
Sum(case when (datediff(DAY,PENDING_TIME, GETDATE())) > 1 AND (datediff(DAY,PENDING_TIME, GETDATE())) < 30 then 1 Else 0 End) as '1 month', 
Sum(case when datediff(DAY,PENDING_TIME, GETDATE()) >= 30 then 1 Else 0 End) as 'More than month' 
from ItemsTable where datepart(yyyy,PENDING_TIME) = DATEPART(yyyy,GETDATE()) 

这将返回数据:

30 Min  Over 30 Min Over 1 Hr 1 month  More than month 
----------- ----------- ----------- ----------- --------------- 
100   350  NULL  NULL  NULL 

我想在2列格式的结果为:

30 Min  ------  45 
Over 30  ------ 100 
Over 1 hr ------ null 
Over 1 month ------ null 

我知道的pivot函数,但是我选择的列并不是真的在我正在选择的表中,而是它们是作为聚合函数的结果而创建的。

如何以2列和多行格式获取此内容。

感谢您阅读。

回答

2

您可以创建一个派生列,其通过该列的等待划分为不同的类型,然后组:

With waitCodes As (
    Select Case 
     When DateDiff(Minute, PENDING_TIME, GetDate()) <= 30 Then '30 Min' 
     When DateDiff(Minute, PENDING_TIME, GetDate()) <= 60 Then 'Over 30' 
     When DateDiff(Minute, PENDING_TIME, GetDate()) <= 1440 Then 'Over 1 hr' 
     When DateDiff(Minute, PENDING_TIME, GetDate()) <= 43200 Then '1 month' 
     Else 'More than a month' End As [WaitTime] 
     From ItemsTable 
     Where DatePart(yyyy, PENDING_TIME) = DatePart(yyyy,GetDate())) 
Select [WaitTime], Count(*) As n 
    From waitCodes 
    Group By [WaitTime]; 

另外,我强烈建议你改变Where子句中查询以便它不” t将函数应用于PENDING_TIME列。 There are multiple benefits of this.

... 
Where PENDING_TIME >= Convert(date, Convert(char(4), DatePart(yyyy, GetDate()))+'-01-01 00:00:00.000', 121) 
    And PENDING_TIME < Convert(date, Convert(char(4), DatePart(yyyy, GetDate())+1)+'-01-01 00:00:00.000', 121) 
.... 
+0

很好的解决方案。顺便说一句,替代'WHERE'子句只有在有问题的表没有未来日期的情况下才有效。 – wdosanjos

+0

@wdosanjos优秀的一点。我认为这种情况不会发生,但这可能是一个危险的假设。我已经编辑了相应的建议'WHERE'。 – mendosi

+1

顺便说一句,看看[这里](http://stackoverflow.com/questions/13437362/how-to-get-first-and-last-date-of-current-year)的解决方案如何获得一年中的第一天和最后一天没有字符串操作。 (yy,DATEDIFF(yy,0,getdate()),0)和PENDING_TIME wdosanjos

0

可以跨应用的语句每一部开拓创新的这样的SQL

SELECT c.* FROM 
    (
     SELECT 
      SUM(CASE 
       WHEN datediff(MINUTE, PENDING_TIME,GETDATE()) <= 30 
        THEN 1 ELSE 0 
      END) AS '30 Min', 
      Sum(case when (datediff(MINUTE,PENDING_TIME, GETDATE())) > 30 AND (datediff(MINUTE,PENDING_TIME, GETDATE())) <= 60 then 1 Else 0 End) as 'Over 30 Min', 
      Sum(case when (datediff(MINUTE,PENDING_TIME, GETDATE())) > 60 AND (datediff(HOUR,PENDING_TIME, GETDATE())) <= 24 then 1 Else 0 End) as 'Over 1 Hr', 
      Sum(case when (datediff(DAY,PENDING_TIME, GETDATE())) > 1 AND (datediff(DAY,PENDING_TIME, GETDATE())) < 30 then 1 Else 0 End) as '1 month', 
      Sum(case when datediff(DAY,PENDING_TIME, GETDATE()) >= 30 then 1 Else 0 End) as 'More than month' 
     from ItemsTable where datepart(yyyy,PENDING_TIME) = DATEPART(yyyy,GETDATE()) 
    ) 
    CROSS APPLY(VALUES('30 MIN',a),('Over 30',b),('Over 1 hr',c),('Over 1 month',d),('More than month',e)) c(title,[value]) 

结果:

 
title   value 
--------------- ----------- 
30 MIN   100 
Over 30   350 
Over 1 hr  NULL 
Over 1 month NULL 
More than month NULL