我正在建立一个网站来学习编码,我有一个基于JQuery UI的自动完成,我通过三个MySQL表填充。自动完成的一些问题
这是我上的index.php代码
<script src="./public/js/jquery.js"></script>
<script src="public/js/jquery-ui-1.8.22.custom.min.js" type="text/javascript" charset="utf-8"></script>
<script>
$(function() {
$("#search").autocomplete({
source: "suggest.php",
minLength = 2,
select: function(event, ui) {
log(ui.item ?
"Selected: " + ui.item.value + aka " + ui.item.id :
"Nothing selected, input was " + this.value);
}
});
});
</script>
继承人上的index.php的代码的形式(在我的搜索框和自动完成应该是在页面):
<form class="form-search span8 offset6">
<input type="text" id='search' name='q' autocomplete="off" class="input-medium search-query">
<button type="submit" class="btn btn-warning">GO!</button>
</form>
继承人对suggest.php代码:
<?php
require("./config.php");
$q = $_GET['q'];
$names = '';
$result = mysql_query("SELECT name FROM company WHERE name LIKE '$q%' UNION SELECT cat FROM cat WHERE cat LIKE '$q%' UNION SELECT subcat FROM subcat WHERE subcat LIKE '$q%' LIMIT 10");
$names = array();
while ($row = mysql_fetch_array($result)) {
$names[] = $row['name'];
}
echo json_encode($names);
?>
如果我直接去suggest.php q = SOMETHING和回声出$名字,这是什么出来:
["City Market","Cafes","Cheesesteaks","Chicken Wings","Chinese","CSA","Coffee & Tea","Convenience Stores","Comedy Clubs"]Array
当我打开Chrome的开发者面板旁边有jQuery的用于自动提示说错误“未捕获的SyntaxError:意外的标记=”
我的自动提示未显示出来。怎么了?
感谢您的帮助!
我改变了=要:现在新的错误是“意外的标记非法”和autocomplet仍然没有显示出来......有什么建议?
出于好奇,为什么你既呼应你的阵列的JSON表示,并在你的PHP数组本身? – 2012-08-10 15:49:52
错误说明全部 – Don 2012-08-10 15:50:13
@anthony,oops对不起,我有最后一个回声$名称只是为了测试...不应该在那里 – infinity 2012-08-10 15:52:12