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我想用php SimpleXML和xpath解析XML文件,并且遇到问题,获取路径并访问属性值。任何帮助赞赏。用php和xpath解析xml - 获取路径right
这里是我的xml文件: -
<message:MessageGroup xmlns="http://mynamespace.com">
<Book>
<BookKey>
<Value concept="TITLE" value="Gone Girl"/>
<Value concept="AUTHOR" value="Gillian Flynn"/>
</BookKey>
<Sales>
<Month>Jan</Month>
<Number value="20"/>
</Sales>
<Sales>
<Month>Feb</Month>
<Number value="15"/>
</Sales>
<Sales>
<Month>Mar</Month>
<Number value="30"/>
</Sales>
</Book>
<Book>
<BookKey>
<Value concept="TITLE" value="Inferno"/>
<Value concept="AUTHOR" value="Dan Brown"/>
</BookKey>
<Sales>
<Month>Jan</Month>
<Number value="10"/>
</Sales>
<Sales>
<Month>Feb</Month>
<Number value="15"/>
</Sales>
<Sales>
<Month>Mar</Month>
<Number value="3"/>
</Sales>
</Book>
</message:MessageGroup>
我需要解析此得到以下的输出: -
Gone Girl,Gillian Flynn,Jan,20
Gone Girl,Gillian Flynn,Feb,15
Gone Girl,Gillian Flynn,Mar30
Inferno,Dan Brown,Jan,10
Inferno,Dan Brown,Feb,15
Inferno,Dan Brown,Mar,3
我写了下面的代码: -
<?php
$xmlfile = 'Books.xml';
$xml = simplexml_load_file($xmlfile);
$namespace = 'http://mynamespace.com';
$xml->registerXPathNamespace('ns',$namespace);
$books = $xml->xpath('//ns:Book');
//loop through each book -
foreach($books as $book) {
$values = $xml->xpath('ns:BookKey/Value');
$bookkeys= array();
//loop through each Book's BookKey Values and push them to array -
foreach($values as $value){
array_push($bookkeys, $value->attributes()->value);
}
$sales = $xml->xpath('ns:Sales');
//loop through each Book's Sales and write out Month and Number value after the book key values -
foreach($sales as $sale){
foreach($bookkeys as $bk){
echo $bk.",";
}
echo $sale->Month;
echo ",";
echo $sale->Number->attributes()->value;
echo "\n";
}
}
?>
从var_dump中,$ books数组看起来没问题;尽管$ values和$ sales是空数组,但显然路径并不正确。我已经尝试删除名称空间,但仍然得到一个空数组;我想避免将文件中的所有值和销售情况拉出来,而不是仅仅针对每本特定的书。
“消息”的xmlns在哪里? – 2013-04-26 16:35:14
标准迭代器仅用于默认名称空间中的子节点。您可能正在使用命名空间参数集来查找['SimpleXMLElement :: children()'](http://php.net/SimpleXMLElement.children)。同样适用于['SimpleXMLElement :: attributes()'](http://php.net/SimpleXMLElement.attributes),您还需要传递名称空间,它不会从元素节点继承。 – hakre 2013-04-27 06:41:25