（终止应用程序，由于未捕获的异常'NSInvalidArgumentException）

Question

我正在使用uitableview来显示json解析的数据。解析的数据存储在数组中，并且数组列表100被分配给uitableview。但它摔碎在objectAtIndex 在{for循环}它显示崩溃报告

终止应用程序由于未捕获的异常 'NSInvalidArgumentException'，理由是：“ - [NSMutableArray的insertObject：atIndex：]：尝试插入零在0'对象*

普莱舍帮助我

- (void)viewDidLoad 
{ 
    self.responseData = [NSMutableData data]; 
    NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:openexchangeURl]]; 
    [[NSURLConnection alloc] initWithRequest:request delegate:self]; 
    [super viewDidLoad]; 

} 

- (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response 
{ 
    [responseData setLength:0]; 
} 
- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data 
{ 
    [responseData appendData:data]; 
} 
- (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error { 
    [connection release]; 
    self.responseData = nil; 
} 
- (void)connectionDidFinishLoading:(NSURLConnection *)connection 
{ 
    [connection release]; 

    NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding]; 
    self.responseData = nil; 

    values = [responseString JSONValue]; 
    array = [[NSMutableArray alloc] init]; 
    NSMutableArray *arrTitle = [[NSMutableArray alloc] init]; 
    NSMutableArray *arrValues = [[NSMutableArray alloc] init]; 
    array =[values valueForKey:@"rates"]; 

    NSLog(@"array values:--> %@",array); 
// NSLog(@"values:--> %@",values); 
// NSLog(@"Particular values:--> %@",[[values valueForKey:@"rates"] valueForKey:@"AED"]); 

    tempDict1 = (NSMutableDictionary *)array;    
    NSArray *arr;// =[[NSArray alloc]init]; 
    arr = [[tempDict1 valueForKey:@"rates"] componentsSeparatedByString:@";"]; 
    NSLog(@"arr-->%@",arr); 
    NSString *subStar = @"="; 
    [arrTitle removeAllObjects]; 
    [arrValues removeAllObjects]; 

    for (int i=0; i<[arr count]-1; i++) 
    { 
     [arrTitle addObject:[[arr objectAtIndex:i] substringToIndex:NSMaxRange([[arr objectAtIndex:i] rangeOfString:subStar])-1]]; 
     [arrValues addObject:[[arr objectAtIndex:i] substringFromIndex:NSMaxRange([[arr objectAtIndex:i] rangeOfString:subStar])]]; 
     NSLog(@"arrTitle is:--> %@",arrTitle); 
    } 

    tempDict1 = (NSMutableDictionary*)[array objectAtIndex:0]; 
    array = [values valueForKey:@"rates"]; 
    NSLog(@"tempDict--%@",[tempDict1 objectForKey:@"AED"]); 

    [array retain]; 
    [tbl_withData reloadData]; 

} 
- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView 
{ 
    return 1; 
} 

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section 
{ 
    NSLog(@"array-->%@",array); 
    return [array count]; 

} 

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath 
{ 
    intIndexPath = indexPath.row; 
    static NSString *CellIdentifier = @"Cell"; 

    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; 
    if (cell == nil) 
    { 
     cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; 
     cell.textLabel.adjustsFontSizeToFitWidth = YES; 
     cell.textLabel.font = [UIFont systemFontOfSize:8]; 
     cell.textLabel.numberOfLines = 4; 

    } 

// NSLog(@"data is like:--> %@",array); 
// cell.textLabel.text= [NSString stringWithFormat:@"%@",[array objectAtIndex:intIndexPath]]; 
    cell.textLabel.text =[array objectAtIndex:intIndexPath]; 

    return cell; 
} 

Answer 1

还有就是你的数组中只有一个项目，在这里你刚才添加的一个对象：

array = [[NSMutableArray alloc] init]; 
[array addObject:[values valueForKey:@"rates"]]; 

您应该将从[values valueForKey:@"rates"]获得的值分配给数组变量。还要使数组变量成为保留该值的属性。

@property (nonatomic, strong) NSArray *array; 

然后将其分配给属性：

self.array = [values valueForKey:@"rates"]; 

---

而且将单元格​​的所有造型到这里，如果你创建新的细胞。这会加快速度，因为你不会每次都改变单元格的样式。

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath 
{ 
    static NSString *cellIdentifier = @"Cell"; 
    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:cellIdentifier]; 
    if (cell == nil) { 
     cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:cellIdentifier] autorelease]; 
     cell.textLabel.adjustsFontSizeToFitWidth = YES; 
     cell.textLabel.font = [UIFont systemFontOfSize:8]; 
     cell.textLabel.numberOfLines = 4; 

    } 
    NSLog(@"data is like:--> %@",array); 
    // NSString *cellValue =[array objectAtIndex:indexPath.row]; 
    // cell.textLabel.text = cellValue; 

    cell.textLabel.text= [NSString stringWithFormat:@"%@",[array objectAtIndex:indexPath.row]]; 

    return cell; 
} 

Answer 2

以正确的格式从服务器获取数据...在您的情况下，您的数据位于一个数组中。所以使它在不同的不同阵列..

{"reply":["AED = 3.673188","AFN = 48.5725","","","",""]} 

，或者你可以分析你的反应和单一单数据保存到另一个数组...