我正在编写一个程序,该函数在一个单独的头文件中包含函数声明和定义以及结构定义。 .cpp文件和functions.h文件都位于同一个文件夹中。但是,我始终得到臭名昭着的“架构x86_64的未定义符号:”错误。我已经阅读了许多关于这个错误的其他问题,但我无法解决这个问题。这里是代码:使用头文件编译C++程序时出错:体系结构x86_64的未定义符号
我使用Mac OSX中的终端进行编码。我正在运行优胜美地。但是,我将它复制到Windows并在PuTTY中运行,并且发生了同样的确切错误消息。
对于functions.h头文件:
#ifndef FUNCTIONS_H
#define FUNCTIONS_H
#include <iostream>
#include <string>
#include <fstream>
using namespace std;
struct Books
{
int ISBN;
string Author;
string Publisher;
int Quantity;
double Price;
};
class functions
{
public:
void READ_INVENTORY(Books, int, int);
};
// Function definitions
void READ_INVENTORY(Books* list, int max, int position)
{
cout << "You have chosen to read inventory from a file.\n"
<< "Press ENTER to continue...\n";
cin.get();
ifstream inputFile;
inputFile.open("inventory.dat");
if (!inputFile)
cout << "Error: Input file cannot be found\n";
else
{
inputFile >> list[position].ISBN;
inputFile >> list[position].Author;
inputFile >> list[position].Publisher;
inputFile >> list[position].Quantity;
inputFile >> list[position].Price;
cout << "The following data was read from inventory.dat:\n\n"
<< "ISBN: " << list[position].ISBN << endl
<< "Author: " << list[position].Author << endl
<< "Publisher: " << list[position].Publisher << endl
<< "Quantity: " << list[position].Quantity << endl
<< "Price: " << list[position].Price << endl << endl;
cout << "Press ENTER to return to the main menu...\n";
cin.get();
}
}
#endif
这里是cpp文件:
#include <iostream>
#include <string>
#include <fstream>
#include "functions.h"
using namespace std;
int main()
{
const int MAX_SIZE = 100;
int size, choice;
functions bookstore;
Books booklist[MAX_SIZE];
cout << "Thank you for using Justin's Bookstore Manager\n\n";
do
{
cout << "Please select a choice from the menu below:\n\n"
<< "\t\t MENU\n"
<< "\t----------------------------\n\n"
<< "\t1: Read inventory from a file\n"
cin >> choice;
size = choice;
switch (choice)
{
case 1: bookstore.READ_INVENTORY(booklist[choice], MAX_SIZE, size);
break;
default:
{
cout << "Sorry, that is not a valid selection\n\n";
}
}
} while (choice != 6);
return 0;
}
最后,这里是整个错误消息:
未定义的符号架构x86_64: “functions :: READ_INVENTORY(Books,int,int)”,引用来自: _main in bookstore-96 93df.o 铛:错误:连接命令失败,退出代码1(使用-v看看调用)
所以这是这个归结为:这是错误造成怎样的程序被写入或由外部冲突与程序无关?
C++不是强制执行* pure *面向对象编程的语言。以有意义的方式设计你的类,不要仅仅为了保持功能而创建类。 – 2015-04-02 04:23:31
此外,你显示的代码甚至不会编译,因为你传递的是一个需要指针的函数的引用。 – 2015-04-02 04:24:58