发送表单数据分开

Question

好吧，这是我正在尝试acchomplish，（截至现在）我有用户选择图像和图像的大小，并上传到服务器。我想要做的是在图像被选择并调整大小后停止脚本。然后，我想创建一个函数来上传我选择时调整大小的图像。原因是我打算在我的表单中添加更多输入文本，并且用户已完成完成，然后我想要使用这些文件上传图像。注：我还没有添加文字输入会做后只是希望能够sepearate上传functions..I我不知道如何单独的FORMDATA后部分

JAVASCRIPT

<script> 
function ResizeMe(){ 
var dataurl = null; 
var uniq = 'id' + (new Date()).getTime(); 
var filesToUpload = document.getElementById('input').files; 
var file = filesToUpload[0]; 

// Create an image 
var img = document.createElement("img"); 
// Create a file reader 
var reader = new FileReader(); 
// Set the image once loaded into file reader 
reader.onload = function(e) 
{ 
    img.src = e.target.result; 

    img.onload = function() { 
     var canvas = document.createElement("canvas"); 
     var ctx = canvas.getContext("2d"); 
     ctx.drawImage(img, 0, 0); 

     var MAX_WIDTH = 200; 
     var MAX_HEIGHT = 400; 
     var width = img.width; 
     var height = img.height; 

     if (width > height) { 
      if (width > MAX_WIDTH) { 
      height *= MAX_WIDTH/width; 
      width = MAX_WIDTH; 
      } 
     } else { 
      if (height > MAX_HEIGHT) { 
      width *= MAX_HEIGHT/height; 
      height = MAX_HEIGHT; 
      } 
     } 
     canvas.width = width; 
     canvas.height = height; 
     var ctx = canvas.getContext("2d"); 
     ctx.drawImage(img, 0, 0, width, height); 
     dataurl = canvas.toDataURL("image/jpeg",.2); 
     var blobBin = atob(dataurl.split(',')[1]); 
     var array = []; 
     for(var i = 0; i < blobBin.length; i++) { 
     array.push(blobBin.charCodeAt(i)); 
     } 
     var files = new Blob([new Uint8Array(array)], {type: 'image/jpg', name: "ddd"}); 
     // Post the data 
     var fd = new FormData(); 
     fd.append("image", files, uniq); 
     $.ajax({ 
      url: 'http:///www.***/upload.php', 
      data: fd, 
      cache: false, 
      contentType: false, 
      processData: false, 
      type: 'POST', 
      success: function(data){ 
       $('#form_input')[0].reset(); 
       location.reload(); 
      } 
     }); 
    } // img.onload 
} 
// Load files into file reader 
reader.readAsDataURL(file); 
} 
</script> 

Answer 1

代码发送形式数据是

$.ajax({ 
    url: 'http:///www.***/upload.php', 
    data: fd, 
    cache: false, 
    contentType: false, 
    processData: false, 
    type: 'POST', 
    success: function(data){ 
     $('#form_input')[0].reset(); 
     location.reload(); 
    } 
}); 

该代码是您将要放在一个单独的函数中的代码。要将它移动到其他地方，您必须确保它仍然可以访问所有要发送的变量，即fd。 fd连接到几个变量，全部返回到canvas。你说一次只能有一个画布，所以我们可以使canvas成为一个全局变量，然后从任何地方得到fd都很容易。

<script> 
    //Moved to global so that sendFormStuff will see it 
    var canvas = document.createElement("canvas"); 
    var ctx = canvas.getContext("2d"); 
    function ResizeMe(){ 
    var dataurl = null; 
    var uniq = 'id' + (new Date()).getTime(); 
    var filesToUpload = document.getElementById('input').files; 
    var file = filesToUpload[0]; 

    // Create an image 
    var img = document.createElement("img"); 
    // Create a file reader 
    var reader = new FileReader(); 
    // Set the image once loaded into file reader 
    reader.onload = function(e) 
    { 
     img.src = e.target.result; 

     img.onload = function() { 

     ctx.drawImage(img, 0, 0); 

     var MAX_WIDTH = 200; 
     var MAX_HEIGHT = 400; 
     var width = img.width; 
     var height = img.height; 

     if (width > height) { 
      if (width > MAX_WIDTH) { 
      height *= MAX_WIDTH/width; 
      width = MAX_WIDTH; 
      } 
     } else { 
      if (height > MAX_HEIGHT) { 
      width *= MAX_HEIGHT/height; 
      height = MAX_HEIGHT; 
      } 
     } 
     canvas.width = width; 
     canvas.height = height; 
     ctx.drawImage(img, 0, 0, width, height); 
     } // img.onload 
    } 
    function sendFormStuff() { 
     var dataurl = canvas.toDataURL("image/jpeg",.2); 
     var blobBin = atob(dataurl.split(',')[1]); 
     var array = []; 
     for(var i = 0; i < blobBin.length; i++) { 
     array.push(blobBin.charCodeAt(i)); 
     } 
     var files = new Blob([new Uint8Array(array)], {type: 'image/jpg', name: "ddd"}); 
     // Post the data 
     var fd = new FormData(); 
     fd.append("image", files, uniq); 
     $.ajax({ 
     url: 'http:///www.***/upload.php', 
     data: fd, 
     cache: false, 
     contentType: false, 
     processData: false, 
     type: 'POST', 
     success: function(data){ 
      $('#form_input')[0].reset(); 
      location.reload(); 
     } 
     }); 
    } 
    // Load files into file reader 
    reader.readAsDataURL(file); 
    } 
</script> 

所以真的所有我们在这里所做的就是移动请求代码到一个单独的功能，使canvas和ctx（你被宣布两次，顺便说一句），通过该功能进行访问。