如果条件错误，bash脚本

Question

这是我的第一个bash脚本，用于将我的内容同步到服务器。我想通过要同步的文件夹作为参数。但是，它不能按预期工作。

这是我的脚本（保存为sync.sh）：

echo "STARTING SYNCING... PLEASE WAIT!" 
var="$1" ; 
echo "parameter given is $var" 

if [ "$var"=="main" ] || [ "$var"=="all" ] ; then 
    echo "*** syncing main ***" ; 
    rsync -Paz /home/chris/project/main/ user@remote_host:webapps/project/main/ 
fi 

if [ "$var"=="system" ] || [ "$var"=="all" ] ; then 
    echo "*** syncing system ***" ; 
    rsync -Paz /home/chris/project/system/ user@remote_host:webapps/project/system/ 
fi 

if [ "$var"=="templates" ] || [ "$var"=="all" ] ; then 
    echo "*** syncing templates ***" ; 
    rsync -Paz /home/chris/project/templates/ user@remote_host:webapps/project/templates/ 
fi 

这我的输出：

chris@mint-desktop ~/project/ $ sh ./sync.sh templates 
STARTING SYNCING... PLEASE WAIT! 
parameter given is templates 
*** syncing main *** 
^Z 
[5]+ Stopped     sh ./sync.sh templates 

虽然我给的 “模板” 作为一个参数，它忽略它。为什么？

Answer 1

基于下面的意见，这是我的建议修正后的脚本：

#!/bin/bash 
echo "STARTING SYNCING... PLEASE WAIT!" 
var="$1" ; 
echo "parameter given is $var" 

if [ "$var" == "main" -o "$var" == "all" ] ; then 
    echo "*** syncing main ***" ; 
    rsync -Paz /home/chris/project/main/ user@remote_host:webapps/project/main/ 
fi 

if [ "$var" == "system" -o "$var" == "all" ] ; then 
    echo "*** syncing system ***" ; 
    rsync -Paz /home/chris/project/system/ user@remote_host:webapps/project/system/ 
fi 

if [ "$var" == "templates" -o "$var" == "all" ] ; then 
    echo "*** syncing templates ***" ; 
    rsync -Paz /home/chris/project/templates/ user@remote_host:webapps/project/templates/ 
fi 

Answer 2

您需要在==运算符两边的空间。将其更改为：

if [ "$var" == "main" ] || [ "$var" == "all" ] ; then 
    echo "*** syncing main ***" ; 
    rsync -Paz /home/chris/project/main/ user@remote_host:webapps/project/main/ 
fi