更改的NSTimer这是循环的时间

Question

我有这样的代码，总是打开一个特定的方法，持续4秒：

float timer = 4.0; 

-(void)Start{ 

    [NSTimer scheduledTimerWithTimeInterval:timer 
            target:self 
            selector:@selector(go3) 
            userInfo:nil 
            repeats:YES]; 

} 

-(void)go3{ 

NSLog(@"Show now this messange in 1.0 seconds"); 

timer = 1.0; 


} 

这段代码的问题是，我想修改的时间循环4秒到1秒，但它似乎不工作，将使我的代码的逻辑工作的替代方法是什么？

Answer 1

您需要在下面。

float timer = 4.0; 

-(void)Start{ 

    [NSTimer scheduledTimerWithTimeInterval:timer 
            target:self 
            selector:@selector(go3) 
            userInfo:nil 
            repeats:NO]; 

} 

-(void)go3{ 
    NSLog(@"Show now this messange in 1.0 seconds"); 
    timer = 1.0; 
    [NSTimer scheduledTimerWithTimeInterval:timer 
            target:self 
            selector:@selector(go3) 
            userInfo:nil 
            repeats:YES]; 
} 

Answer 2

NSTimeInterval interval = 4.0f; 

-(void)doSomething 
{ 
    if (something happened) { 
     interval = 1.0f; // change time when you need it 
    }else if (you want to stop it) { 
     return; 
    } 
    [self performSelector:@selector(doSomething) withObject:nil afterDelay:interval]; 
}