如何检查mysql表的boolean字段，并将0或1的值转换为true/false在php

Question

在我的查询中，我有3个tinyint字段，它们通过获取给出0/1值。但是在获取所有我想要将结果编码为JSON格式的数据之后，应该得到true/false而不是0/1。 在我的代码中，我做了类型转换，它给出了正确的结果。但我应该写下所有我不想要的tinyint字段。 是否有任何方法来检查tinyint字段和转换。

PHP CODE: 


$result= mysql_query("select incident_main.inc_id as incident_id, 
         ward_master.ward_id as 'ward_id', 
         GROUP_CONCAT(incident_log.inclog_date) as revisit_dates , 
         inc_GISlat as lat, 
         inc_GISlon as lon, 
      inc_closed as b_is_closed, 
       inc_closeDate as closed_date, 
         incident_statuscd.inc_status_desc as status, 
         inc_date as 'incident_date', 
         inc_patientName as 'patient_name', 
         inc_patientAge as 'patient_age', 
         inc_patientGender as 'patient_gender', 
         inc_patientMobile as'patient_mobile' , 
         inc_patientAddress as 'patient_address', 
         inc_type as type, 
         inc_typeOther as 'type_other', 
         inc_diagnosis as diagnosis, 
         inc_recurrence as recurrence, 
       inc_hospitalized as b_hospitalized, 
         inc_treatment as treatment , 
         inc_treatmentOther as 'treatment_other' 
        from 
         incident_main, 
         incident_statuscd , 
         ward_master, 
         incident_log 
        where 
         inc_status=incident_statuscd.inc_status_id 
        and 
         incident_main.inc_patientWard=ward_master.ward_id 
        and incident_log.inc_id=incident_main.inc_id ") 
         or die(mysql_error); 
while($res = mysql_fetch_assoc($result)) { 
foreach($res as $key => $value) { 
    if(substr($key, 0, 2) === "b_") { 
     // assign new value 
     $res[substr($key,2,strlen($key))] = !!$value; 
     //clean up old value 
     unset($res[$key]); 
     }; 

    } 
    $data=array_filter($res); 

echo json_encode($data, true); 

请帮忙!! 在此先感谢。

Answer 1

PHP中

检查TINYINT你可以做的是用B_预先考虑的变量，并使用正则表达式/ strpos/SUBSTR来筛选，以强制转换到这一点布尔没有真正的方法。这样，你只需要调整你的查询，脚本就会为你做铸件。

$result= mysql_query("select incident_main.inc_id as incident_id, 
         ward_master.ward_id as 'ward_id', 
         GROUP_CONCAT(incident_log.inclog_date) as revisit_dates , 
         inc_GISlat as lat, 
         inc_GISlon as lon, 
    --->    inc_closed as b_is_closed, 
    --->    inc_reviewed as b_is_reviewed, 
         inc_closeDate as closed_date, 
         incident_statuscd.inc_status_desc as status, 
         inc_date as 'incident_date', 
         inc_patientName as 'patient_name', 
         inc_patientAge as 'patient_age', 
         inc_patientGender as 'patient_gender', 
         inc_patientMobile as'patient_mobile' , 
         inc_patientAddress as 'patient_address', 
         inc_type as type, 
         inc_typeOther as 'type_other', 
         inc_diagnosis as diagnosis, 
         inc_recurrence as recurrence, 
    --->    inc_hospitalized as b_hospitalized, 
         inc_treatment as treatment , 
         inc_treatmentOther as 'treatment_other' 
        from 
         incident_main, 
         incident_statuscd , 
         ward_master, 
         incident_log 
        where 
         inc_status=incident_statuscd.inc_status_id 
        and 
         incident_main.inc_patientWard=ward_master.ward_id 
        and incident_log.inc_id=incident_main.inc_id ") 
         or die(mysql_error); 
while($res = mysql_fetch_assoc($result)) { 
foreach($res as $key => $value) { 
    if(substr($key, 0, 2) === "b_") { 
     // assign new value 
     $res[substr($key,2,strlen($key))] = !!$value; 
     //clean up old value 
     unset($res[$key]); 
    } 
    } 
    $data=array_filter($res,'not_null'); 
} 


function not_null($test) { 
    return !($test === null); 
} 

EDIT

加入一种方法来恢复的布尔标记键为正常的代码执行原始值。 是它的重复，但可能有助于进一步的实现/代码执行，而无需重命名所有内容b_

Answer 2

JS代码：

if(1) 
    alert('true'); 
if(0) 
    alert('false'); 

Answer 3

试着写另一个功能：

private function isTrue($input){ 
    if ((bool)$input){ 
      return "true"; 
    }else{ 
      return "false"; 
    }   
} 

当与0或1返回文本称为 “真” 或 “假”。然后加入呼吁要编码的每个TINYINT：

... 
$row['hospitalized'] = isTrue($row['hospitalized']); 
... 

Answer 4

不幸的是，有没有办法在PHP区分TINYINT和integer。因此，您需要列出要转换的字段。这样做的缩短版本如下所示：

$a = ['a' => 1, 'b' => 100, 'c' => 0 ]; 
$bools = ['a', 'c']; // list of fields to transform 

$result = array_map(function($item) use($bools,&$a) { 
    $key=key($a); next($a); // we need a key to check it’s name 
    return in_array($key, $bools) ? (bool)$item : $item; 
}, $a); 

print_r(json_encode($result, true)); 
//⇒ {"a":true,"b":100,"c":false} 

如果并且只有key在$bools阵列列出后者将投integerbool到。有关更多详细信息，请参阅array_map docs。

希望它有帮助。