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我即三个表:雄辩:如何获得逆
- 人(含列:ID &名)
- 分配(与列:PERSON_ID & PROJECT_ID)
- 项目(列:编号&标题)
我有Assignments表,因为每个人都可以分配给许多项目。
我有这三种模式:
// People.php
public function projectAssigned()
{
return $this->hasMany('App\Assignment', 'person_id');
}
// Assignment.php
public function person()
{
return $this->belongsTo('App\People', 'person_id');
}
public function project()
{
return $this->belongsTo('App\Project', 'project_id');
}
public function task()
{
return $this->hasMany('App\Task', 'assignment_id');
}
// Project.php
public function assignment()
{
return $this->hasMany('App\Assignment', 'project_id');
}
获得的特定项目中分配的人的名单很简单:
how I get it:
@foreach($project->assignment as $person)
<tr>
<td>{{$person->person->firstname.' '.$person->person->lastname}}</td>
</tr>
@endforeach
我的问题是:如何让人们名单未在特定项目中分配?