我试图执行搜索,以便用户可以输入书的标题,laravel将浏览数据库并显示匹配任何字符的结果。调用未定义的方法Illuminate Database Query Builder :: title()
我的'书籍'表包含'标题'字段。
但是如果我例如 'F' 我得到的输入:
调用未定义的方法照亮\数据库\查询\生成器::标题()
搜索刀片:
@extends('layouts.master')
@section('title')
@section('content')
<h1>Search for books</h1>
<form action="{{url('details')}}" method="POST">
{{ csrf_field() }}
<div>
<input type='text' name='book' placeholder='Enter any character' />
</div>
<input type="submit" name="submitBtn" value="Search">
</form>
@endsection
详细=结果页面:
@extends('layouts.master')
@section('title')
@section('content')
<h1>User Details</h1>
<form>
<p>
<ul>
@foreach ($books as $book)
<a href= "{{url('reader/'.$book->title)}}">
{{$book->title}}</a>
</p>
</form>
@endforeach
</ul>
@endsection
控制器:
function search()
{
$books = Book::all();
return view('layouts/search',['books' => $books]);
}
function details() {
$searchTerms = explode(' ', \Request::input('book'));
$books = Book::whereHas('title', function($query) use($searchTerms) {
if(!empty($searchTerms)){
for
each($searchTerms as $book) {
$query->where('book', 'LIKE', '%'. $book .'%');
}
}
})->first();
return view('layouts/details', compact('book'));
}
更新::
function search()
{
$books = Book::all();
return view('layouts/search',['books' => $books]);
}
function details() {
$searchTerms = explode(' ', \Request::input('book'));
$books = Book::where(function($q) use($searchTerms) {
foreach ($searchTerms as $book) {
$q->orWhere('title', '%'.$book.'%');
}
})->first();
return view('layouts/details', compact('books'));
}
你的缩进是一个烂摊子。你试图在查询时调用模型列(在用' - > get()'/ -'> first()'/' - > paginate()')结束查询之前。 – devk
由于在视图中需要集合,因此可以使用' - > get()'或' - > paginate()'。在返回视图以检查查询实际返回的内容之前,还可以使用'dd($ books);'进行调试。 – Robert