日期12月视图

Question

我用PHP工作的显示阵列/ MySQL的

我有两个COLS（日期，现金）与像{7/2001的值表：$ 100，12/2001：$ 50， 1/2002：30 $，5/2002：90 $，6/2003：80 $，9/2003：20 $}我想制作有cols的现金流量表（1月，2月，3月，......） ........ Dec），并且在日期列表中每年都排一次，表格单元格中的现金价值也像打击一样。

如何显示此阵列{7/2001：100 $，12/2001：50 $，1/2002：30 $，5/2002：90 $，6/2003：80 $，9/2003：20 $}如同打击

  |Jan | Feb | Mar | Apr | May | Jun | Jul | Aug | Sep | Oct | Nov | Dec | 
--------+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ 
2001 | 0 | 0 | 0 | 0 | 0 | 0 | 100$ | 0 | 0 | 0 | 0 | 50$ | 
--------+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ 
2002 | 30$ | 0 | 0 | 0 | 90$ | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 
--------+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ 
2003 | 0 | 0 | 0 | 0 | 0 | 80$ | 0 | 0 | 20$ | 0 | 0 | 0 | 

确定这一点，从数据库retrive行，并在表中提取它的代码（日期，现金）之类的阵列

mysql_connect("localhost","",""); 
    mysql_select_db(""); 
    $var3=$_REQUEST['order_num']; 
    $cashtotal=0; 
    $summat = mysql_query("SELECT * FROM cash_flow WHERE order_num='$var3'"); 
    while ($row = mysql_fetch_assoc($summat)) { 
     print "<tr>"; 
     print "<td>$row[cash_date]</td>"; 
     print "<td>$row[cash]</td>"; 
     print "</tr>"; 
    } 

Answer 1

$array = array ("7/2001:100$", "12/2001:50$" , "1/2002:30$" , "5/2002:90$" , "6/2003:80$","9/2003:20$"); 

    $prefill = array_fill(1,12,0); 
    $years_array = array(); 

    foreach($array as $value){ 
     list($date , $amount) = explode(":" , $value); 
     list($month , $year) = explode("/" , $date); 

     if(!$years_array[$year]) $months_data = $prefill; 
     else $months_data = $years_array[$year]; 

     $months_data[$month] = $amount; 
     $years_array[$year] = $months_data; 
    } 

    echo "| Jan | Feb | Mar | Apr | May | Jun | Jul | Aug | Sep | Oct | Nov | Dec | <br>"; 
    ksort($years_array); 
    foreach($years_array as $year => $year_row){ 
     echo $year." | "; 
     echo implode(" | " , $year_row); 
     echo "<br>"; 
    } 

这应该给你的数据的格式你需要的格式，当然你需要引入一个表格来使列宽正确。

编辑： 在提供通过DB创建数组并把它传递给上面的代码，大概是这样的数据来看：

$array = array(); 
    while ($row = mysql_fetch_assoc($summat)) { 
     $array[] = $row[cash_date].":".$row[cash]; 
    } 

Ofcourse，你可以改善上述2个的代码块，但是这应该给你这个想法。