我想总结一个非常大的数字。我得到的数字长度为
l = answer.bitLength()
但我无法弄清楚如何使用For循环增加每个数字。有任何想法吗?我正在使用java.math.biginteger
。如何在VB.Net中使用与biginteger相当的indexof()?
Visual Studio 2005的2.0版
我还要补充一点,我似乎无法使用<>或任何与我使用的BigInteger的简单的数学选项。如果有人能告诉我如何使用不同的大整数,我会更愿意交换。
Dim answer As java.math.BigInteger
Dim sum As Integer = 0
Dim x As Integer
Dim i As Integer
'Sets value of answer equal to 1
answer = java.math.BigInteger.valueOf(1)
'gets 100!
For i = 1 To 100
answer = answer.multiply(java.math.BigInteger.valueOf(i))
Next
'gets length of answer
Dim l As Integer
l = answer.bitLength()
'Sums up digits in 100!
For x = 0 To l - 1
'Need to pull each character here to add them all up
Next
总结数字的最终解决方案。感谢togoghe。
Dim r As Integer
Dim s As Integer
s = 0
While (answer.compareTo(java.math.BigInteger.valueOf(0)) > 0)
r = answer.mod(java.math.BigInteger.valueOf(10)).ToString()
s = s + r
answer = answer.divide(java.math.BigInteger.valueOf(10))
End While
你试过了什么?你能发表你想要做什么的伪代码吗? – Oded 2011-01-25 20:56:21
没有`System.Numerics.BigInteger`的`bitLength`(甚至是`BitLength`)成员。你确定你没有考虑Java吗? – LukeH 2011-01-25 21:01:52