如何根据指定的给定数组值将数组值转换为逗号分隔的字符串..？

Question

我有阵列下面

Array 
(
    [5] => Array 
    (
    [id] => 5 
    [first_name] => Diyaa 
    [profile_pic] => profile/user5.png 
) 

    [8] => Array 
    (
    [id] => 8 
    [first_name] => Raj 
    [profile_pic] => profile/user8.png 
) 

    [12] => Array 
    (
    [id] => 12 
    [first_name] => Vanathi 
    [profile_pic] => profile/user12.png 
) 

    [15] => Array 
    (
    [id] => 15 
    [first_name] => Giri 
    [profile_pic] => profile/user15.png 
) 

    [19] => Array 
    (
    [id] => 19 
    [first_name] => Mahesh 
    [profile_pic] => profile/user19.png 
) 
) 

作为指定的I具有另一阵列下面

Array 
(
    [0] => 8 
    [1] => 15 
    [2] => 19 
) 

我想从第一阵列的first_name给出，基于第二阵列值=>8,15和19。
所以我需要Raj，Giri，Mahesh作为逗号分隔的字符串输出。
如何得到这.. ..？

Answer 1

该代码会为你工作： -

$array1 = array_column($array, 'first_name','id'); 
$array2 = [8,15,19]; 
$names = array_intersect_key($array1, array_flip($array2)); 
$names = implode(',',$names); 
echo $names; 

Answer 2

试试这个：

$namesArr = []; 
foreach ($wantedIds as $wantedId) { 
    $namesArr[] = $array[$wantedId]['first_name']; 
} 
$namesStr = implode(',', $namesArr); 

echo $namesStr; // Returns 'Raj,Giri,Mahesh' 

我定义$array和$wantedIds如下：

$array = [ 
    5 => [ 
     'id'   => 5, 
     'first_name' => 'Diyaa', 
     'profile_pic' => 'profile/user5.png', 
    ], 
    8 => [ 
     'id'   => 8, 
     'first_name' => 'Raj', 
     'profile_pic' => 'profile/user8.png', 
    ], 
    12 => [ 
     'id'   => 12, 
     'first_name' => 'Vanathi', 
     'profile_pic' => 'profile/user12.png', 
    ], 
    15 => [ 
     'id'   => 15, 
     'first_name' => 'Giri', 
     'profile_pic' => 'profile/user15.png', 
    ], 
    19 => [ 
     'id'   => 19, 
     'first_name' => 'Mahesh', 
     'profile_pic' => 'profile/user19.png', 
    ], 
]; 

$wantedIds = [8, 15, 19]; 

Answer 3

尝试了这一点：

$names = []; 
foreach ($MainArray as $aIndex => $aPayload) // loop over the key and values of the first array 
{ 
    foreach ($searchArray as $b) // loop over your search array (we don't care about the indicies) 
    { 
     if ($aIndex == $b) // match up the index of the first array with the values of the second array 
     { 
      $names[] = $b['first_name'];// append the name to the return array 
      break; // since we've found the index break out of the inner loop 
     } 
    } 
} 

Answer 4

这里我们使用array_column和array_intersect_key来获得所需的输出。

Try this code snippet here

$result=array(); 
$result= array_column($array, "first_name","id"); 
$result=array_intersect_key ($result, array_flip($values)); 
echo implode(",",$result); 

Answer 5

<?php 
    $abc = [ 
     ['id' => 5, 'firstname' => 'Diyya', 'profile_pic' => 'profile/user5.png'], 
     ['id' => 8, 'firstname' => 'Raj', 'profile_pic' => 'profile/user8.png'], 
     ['id' => 12, 'firstname' => 'Vanathi', 'profile_pic' => 'profile/user12.png'] 
    ]; 

    $d = [8, 5, 12]; 

    $output = []; 
    foreach ($abc as $user) { 
     if (in_array($user['id'], $d)) { 
      $output [] = $user['firstname']; 
     } 
    } 
    echo implode(",", $output); 
?> 

Answer 6

还有其他的答案是明智的使用array_intersect_key()和array_column()然而，他们用他们在错误的顺序。数组应该先被过滤，以便array_column()正在处理更小的数组。此外，由于您的子阵列已经有代表其内部值的密钥，因此不需要使用array_column()的参数index_key。这将是最简单，最直接的一个班轮你可以：

输入：

$array = [ 
    5 => [ 
     'id'   => 5, 
     'first_name' => 'Diyaa', 
     'profile_pic' => 'profile/user5.png', 
    ], 
    8 => [ 
     'id'   => 8, 
     'first_name' => 'Raj', 
     'profile_pic' => 'profile/user8.png', 
    ], 
    12 => [ 
     'id'   => 12, 
     'first_name' => 'Vanathi', 
     'profile_pic' => 'profile/user12.png', 
    ], 
    15 => [ 
     'id'   => 15, 
     'first_name' => 'Giri', 
     'profile_pic' => 'profile/user15.png', 
    ], 
    19 => [ 
     'id'   => 19, 
     'first_name' => 'Mahesh', 
     'profile_pic' => 'profile/user19.png', 
    ], 
]; 
$search_keys=[8, 15, 19]; 

方法（Demo）：

echo implode(',',array_column(array_intersect_key($array,array_flip($search_keys)),'first_name')); 

说明：

• 首先将键/值从$search_keys
• 然后使用array_intersect_key()过滤掉不想要的子阵列
• 然后使用array_column()创建first_name值
• 的新数组然后用逗号一起胶水他们创建一个字符串。

输出：

Raj,Giri,Mahesh 

...这就是答案，未来的SO读者应该学习和贯彻。不幸的是，由于它的投票少，不穿绿色的勾号，它可能会被忽略。
:(